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• ffmpeg : how to prevent wait in case of error

  14 février, par xrfang

  I use ffmpeg to add watermark to images/videos, using the following command line :

  


  ffmpeg -y -f mjpeg -i input -i /tmp/watermark.png -filter_complex "..." -f mjpeg output


  


  The problem is, in case the input file is not a jpeg file, the process will HANG instead of quit with an error :

  


  Press [q] to stop, [?] for help
[mjpeg @ 0x126dc60] dqt: len 28602 is too large
Error while decoding stream #0:0: Invalid data found when processing input
frame=    0 fps=0.0 q=0.0 size=       0kB time=-577014:32:22.77 bitrate=  -0.0kbits/s speed=N/A


  


  In my situation, the file has no extension, and I have to specify -f. In case I got the file type wrong, it is an acceptable bug, which I can fix as soon as I found such problem. However it is not good for me if ffmpeg hangs without returning to the parent process, because I have a very large queue of files to process, and I don't want any bug to block the processing task.

  


• node ffmpeg module stuck more than one file

  29 mai 2021, par Muhammad Hamza

  when I read more than one file it will be stuck and also hang my pc. I need to restart my pc

  


  on one file or 5 files it will work perfectly but not more than 5 files

  


  if anyone know this issue let me know

  


  const ffmpegPath = require('@ffmpeg-installer/ffmpeg').path
const ffmpeg = require('fluent-ffmpeg')
ffmpeg.setFfmpegPath(ffmpegPath)


const testFolder = './videos/';
const fs = require('fs');

 


fs.readdir(testFolder, async(err, files) => {
  try {
    for(let i = 0; i < 10; i++){
      if(files[i] != '1 Surah Fatiha Dr Israr Ahmed Urdu - 81of81.mp4'){
        
        let converter = await ffmpeg(`./videos/${files[i]}`)
        await converter.setStartTime('00:00:00').setDuration('30').output(`./outputfolder/${files[i]}`).on('end', function(err) {
        if(err) { 
          console.log(`err durinng conversation \n ${err}`) 
        }
        else{
          console.log(`Done ${files[i]}`);
        }
        }).on('error', function(err){
          console.log(`error: ${files[i]}`, err)
        }).run()
      }
    }
  } catch (error) {
    console.log(error)
  }
});



  


• "Cannot read property 'url' of undefined" even though it's already defined

  28 novembre 2020, par Levi Stancz

  I'm making a Discord music Bot and I'm having trouble with an error saying

  


  TypeError: Cannot read property 'url' of undefined


  


  I tried console logging it and it showed me the url, so I don't understand what is the problem with my code.

  


  Here's my code :

  


  //musicBOT
const Discord = require('discord.js');
const client = new Discord.Client();
const ytdl = require('ytdl-core');
const mcPrefix = '.';

const queue = new Map();

client.on('ready', () => console.log('Music bot ready!'));

client.on('message', async message => {
    if(message.author.bot) return;
    if(!message.content.startsWith(mcPrefix)) return;

    const args = message.content.substring(mcPrefix.length).split(" ");
    const serverQueue = queue.get(message.guild.id);

    if(message.content.startsWith(`${mcPrefix}play`)) {

        const voiceChannel = message.member.voice.channel;
        if(!voiceChannel) return message.channel.send("Hang-szobában kell lenned zenelejátszáshoz.");
        const permissions = voiceChannel.permissionsFor(message.client.user);
        if(!permissions.has('CONNECT')) return message.channel.send("Nincs jogosultságom csatlakozni a hangszobához.");
        if(!permissions.has('SPEAK')) return message.channel.send("Nincs jogosultságom megszólalni ebben a hangszobában.");

        const songInfo = await ytdl.getInfo(args[1])
        const song = {
            title: songInfo.title,
            url: songInfo.videoDetails.video_url
        }

        if(!serverQueue) {
            const queueConstruct = {
                textChannel: message.channel,
                voiceChannel: voiceChannel,
                connection: null,
                songs: [],
                volume: 5,
                playing: true
            }
            queue.set(message.guild.id, queueConstruct)

            queueConstruct.songs.push(song)

            try{
                var connection = await voiceChannel.join();
                message.channel.send(`${song.title} lejátszása.`)
                queueConstruct.connection = connection
                play(message.guild, queueConstruct.songs[0])
            }catch(e){
                console.log(`Hiba csatlakozás közben itt: ${e}`);
                queue.delete(message.guild.id)
                return message.channel.send(`Hiba volt a csatlakozás közben itt: ${e}`)
            }
        } else{
            serverQueue.songs.push(song)
            return message.channel.send(`**${song.title}** hozzáadva a lejátszási listához.`)
        }
        return undefined
        

        
    }else if (message.content.startsWith(`${mcPrefix}stop`)) {
        if(!message.member.voice.channel) return message.channel.send("Hang-szobában kell lenned ahhoz, hogy leállítsd a zenét.")
        if(!serverQueue) return message.channel.send("There is nothing playing")
        serverQueue.songs= []
        serverQueue.connection.dispatcher.end()
        message.channel.send("Sikeresen megálltottad a zenét.")
        return undefined
    }else if(message.content.startsWith(`${mcPrefix}skip`)){
        if(!message.member.voice.channel) return message.channel.send("Hang-szobában kell lenned a skip parancshoz.")
        if(!serverQueue) return message.channel.send("There is nothing playing")
        serverQueue.connection.dispatcher.end()
        message.channel.send("Zene továbbléptetve.")
        message.channel.send(`${song.title} játszása.`)
        
        return undefined
    }

    function play(guild, song) {
        const serverQueue = queue.get(guild.id)
    
        if(!serverQueue.songs){
            serverQueue.voiceChannel.leave()
            queue.delete(guild.id)
            return
        }
    
        const dispatcher = serverQueue.connection.play(ytdl(song.url))
            .on('finish', () => {
                serverQueue.songs.shift()
                play(guild, serverQueue.songs[0])
            })
            .on('error', error => {
                console.log(error)
            })
            dispatcher.setVolumeLogarithmic(serverQueue.volume / 5)
    }

})
//musicBOT


  


  and here is the full error :

  


  const dispatcher = serverQueue.connection.play(ytdl(songInfo.url))&#xA;                                                                     ^&#xA;TypeError: Cannot read property &#x27;url&#x27; of undefined&#xA;    at play (C:\Users\Levi\Desktop\Discord BOT Javascript\bot.js:97:70)&#xA;    at StreamDispatcher.<anonymous> (C:\Users\Levi\Desktop\Discord BOT Javascript\bot.js:100:17)&#xA;    at StreamDispatcher.emit (node:events:388:22)&#xA;    at finish (node:internal/streams/writable:734:10)&#xA;    at processTicksAndRejections (node:internal/process/task_queues:80:21)&#xA;</anonymous>

  


  I started searching on the internet but found nothing about it, I guess my basic javascript knowledge is just not enough.