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Autres articles (60)
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Les autorisations surchargées par les plugins
27 avril 2010, parMediaspip core
autoriser_auteur_modifier() afin que les visiteurs soient capables de modifier leurs informations sur la page d’auteurs -
HTML5 audio and video support
13 avril 2011, parMediaSPIP uses HTML5 video and audio tags to play multimedia files, taking advantage of the latest W3C innovations supported by modern browsers.
The MediaSPIP player used has been created specifically for MediaSPIP and can be easily adapted to fit in with a specific theme.
For older browsers the Flowplayer flash fallback is used.
MediaSPIP allows for media playback on major mobile platforms with the above (...) -
Support audio et vidéo HTML5
10 avril 2011MediaSPIP utilise les balises HTML5 video et audio pour la lecture de documents multimedia en profitant des dernières innovations du W3C supportées par les navigateurs modernes.
Pour les navigateurs plus anciens, le lecteur flash Flowplayer est utilisé.
Le lecteur HTML5 utilisé a été spécifiquement créé pour MediaSPIP : il est complètement modifiable graphiquement pour correspondre à un thème choisi.
Ces technologies permettent de distribuer vidéo et son à la fois sur des ordinateurs conventionnels (...)
Sur d’autres sites (10248)
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Revision f3d8e315ac : Fix a bug in neon that has not save and restore q4-q7 registers. Change-Id : Ie2
27 février 2014, par hkuangChanged Paths :
Modify /vp9/common/arm/neon/vp9_iht8x8_add_neon.asm
Fix a bug in neon that has not save and restore q4-q7 registers.Change-Id : Ie21b5ae89100389b80f919710839084f935a8545
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Java - RTSP save snapshot from Stream Packets
9 août 2016, par Guerino RodellaI’m developing an application which requests snapshots to DVR and IP Cameras. The device I’m working on just offer RTSP requests to do so. Then I implemented the necessary RTSP methods to start receiving the stream packets and I started receiving then via UDP connection established. My doubt is, how can I save the received data to a jpeg file ? Where’s the begging and end of the image bytes received ?
I searched a lot libraries which implement this type of service in Java, like Xuggler ( which it’s maintained no more ), javacpp-presets - has ffmpeg and opencv libraries included - I had some environment problems with it. If someone know an easy and good one which saves snapshots from the streams, let me know.
My code :
final long timeout = System.currentTimeMillis() + 3000;
byte[] fullImage = new byte[ 1024 * 1024 ];
DatagramSocket udpSocket = new DatagramSocket( 8000 );
int lastByte = 0;
// Skip first 2 packets because I think they are HEADERS
// Since I don't know what they mean, I just print then in hexa
for( int i = 0; i < 2; i++ ){
byte[] buffer = new byte[ 1024 ];
DatagramPacket dataPacket = new DatagramPacket( buffer, buffer.length );
udpSocket.receive( dataPacket );
int dataLenght = dataPacket.getLength();
buffer = Arrays.copyOf( buffer, dataLenght );
System.out.println( "RECEIVED[" + DatatypeConverter.printHexBinary( buffer ) + " L: " + dataLenght );
}
do{
byte[] buffer = new byte[ 1024 ];
DatagramPacket dataPacket = new DatagramPacket( fullImage, fullImage.length );
udpSocket.receive( dataPacket );
System.out.println( "RECEIVED: " + new String( fullImage ) );
for( int i = 0; i < buffer.length; i++ ){
fullImage[ i + lastByte ] = buffer[ i ];
lastByte ++;
}
} while( System.currentTimeMillis() < timeout );
// I know this timeout is wrong, I should stop after getting full image bytesThe output :
RECEIVED : 80E0000100004650000000006742E01FDA014016C4 L : 21
RECEIVED : 80E00002000046500000000068CE30A480 L : 17
RECEIVED : Tons of data from the streaming...
RECEIVED : Tons of data from the streaming...
RECEIVED : Tons of data from the streaming...
[...]As you might suppose, the image I’m saving into a file is not readable because I’m doing it wrong. I think the header provide me some info about the next packets the server will sent me telling the start and the end of the image from the streaming. But I don’t understood them. Someone know how to solve it ? Any tips are welcome !
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Save FFMPEG mp4 output to tempfile using Paperclip
31 mars 2021, par aminhsI am trying to save the mp4 output result to a tempfile when ffmpeg concatenates two mp4 input files using the Paperclip run command. After I run the command the tempfile is always empty with text/plain format.


This is my code :


output = Tempfile.new(["join_video_", ".mp4"], binmode: true)
Paperclip.run("ffmpeg -i /path/to/Video/one.mp4 -i /path/to/Video/two.mp4 -filter_complex \"[0:v][1:v]concat=n=2:v=1:a=0[outv]\" -map \"[outv]\" -f mp4 #{File.expand_path(output.path)}")
output.rewind
output.close



I am interested in knowing how to save the mp4 output result to a tempfile from the ffmpeg concatenation rather than knowing how to concatenate two mp4 video files.


Thank you in advance.