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• Why images are combined (ffmpeg) ?

  27 novembre 2020, par Jin X

  I want to create video from images (one image per frame).

  


  ffmpeg -framerate 21.533 -i %d.bmp -i z.wav -r 21.533 -t 120 -map 0:v:0 -map 1:a:0 -c:v libx265 -c:a aac -b:a 128k z.mp4

  


  When I watch resulting video I see (at least at the end of video) that frames are combined with each other (2 images on each frame overlaps with different transparency ratio). I seems like when source and destination frame rate mismatch.

  


  I can remove -framerate and -r options but result will be the same (with 25 fps).

  


  What's the problem ?
How to fix it ?

  


• How to setup ffmpeg for linux server

  1er décembre 2014, par hitesh

  I need to create a screen shot from video,

  I have followed this tutorial to do the intial setup in window 8, php 5.3

  1) I downloaded the ffmpeg from here -[
  http://ffmpeg.zeranoe.com/builds/ ] for 64 bit operating system.

  2) I followed the https://www.youtube.com/watch?v=gU49GiWGGAI , video and did all configuration successfully and phpinfo() shows that ffmpeg has been installed.

  3) Then I tried this to find out whether it is working or not,

  It worked successfully

  4) Next I followed this video tutorial here and thumbnails were created successfully.

  below is my code

  /**
  
   * FFMPEG-PHP Test Script
  
   *
  
   * Special thanks to http://www.sajithmr.me/ffmpeg-sample-code for this code example!
  
   * See the tutorial at http://myownhomeserver.com on how to install ffmpeg-php.
  
   */
  
  error_reporting(1);
  
  error_reporting(E_ALL ^ E_NOTICE);
  
  // Check if the ffmpeg-php extension is loaded first
  
  extension_loaded('ffmpeg') or die('Error in loading ffmpeg');
  
  
  
  // Determine the full path for our video
  
  $vid = realpath('./videos/myvideo.mp4');
  
  $videosize = filesize($vid);
  
  $remoteVideo = 'http://video-js.zencoder.com/oceans-clip.mp4';
  
  
  
  //ffmpeg
  
  
  
  $ffmpeg = dirname(__FILE__) . "\\ffmpeg\\bin\\ffmpeg";
  
  $imageFile = "1.png";
  
  $image2 = "2.png";
  
  $size = "120x90";
  
  $getfromsecond = 7;
  
  $cmd = "$ffmpeg -i $vid -an -ss $getfromsecond -s $size $imageFile";
  
  $cmd2 = "$ffmpeg -i $remoteVideo -an -ss $getfromsecond -s $size $image2";
  
  if(!shell_exec($cmd)){
  
      echo "Thumbnail created";
  
  }else{
  
      echo "Error Creating thumbnail";
  
  }
  
  
  
  if(!shell_exec($cmd2)){
  
      echo "Thumbnail for remote url was created";
  
  }else{
  
      echo "Error Creating thumbnail for remote url ";
  
  }

  ---

    OUTPUT
  
      Thumbnail created
  
      Thumbnail for remote url was created

  Now above code works as expected in my local, in window machine , I need to do it in my server environment(Linux server) with php 5.5. How do I do the configuration for ffmpeg in linux server with php 5.5.

• Anomalie #4579 : Deprecated en php 8 à la création d’un article

  19 octobre 2020, par b b

  Vu https://php.watch/versions/8.0/deprecate-required-param-after-optional => solution simple, remplacer $do par $do = 'aff' comme dans inc_chercher_rubrique_dist(), à discuter.