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Publier sur MédiaSpip
13 juin 2013Puis-je poster des contenus à partir d’une tablette Ipad ?
Oui, si votre Médiaspip installé est à la version 0.2 ou supérieure. Contacter au besoin l’administrateur de votre MédiaSpip pour le savoir -
Des sites réalisés avec MediaSPIP
2 mai 2011, parCette page présente quelques-uns des sites fonctionnant sous MediaSPIP.
Vous pouvez bien entendu ajouter le votre grâce au formulaire en bas de page. -
HTML5 audio and video support
13 avril 2011, parMediaSPIP uses HTML5 video and audio tags to play multimedia files, taking advantage of the latest W3C innovations supported by modern browsers.
The MediaSPIP player used has been created specifically for MediaSPIP and can be easily adapted to fit in with a specific theme.
For older browsers the Flowplayer flash fallback is used.
MediaSPIP allows for media playback on major mobile platforms with the above (...)
Sur d’autres sites (13386)
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ffmpeg error : Unable to find a suitable output format for 'scale=1500:1000'
13 février 2021, par Tomáš Zato - Reinstate MonicaI am trying to convert a bunch of images into a video. The original image resolution is 6000x4000, but if I use ffmpeg to create a video with that resolution, no player can even play it because it's way to huge.


I tried to set the output resolution as such, dividing the input resolution by 4 :


ffmpeg -r 60 -s 1500x1000 -start_number 3790 -i DSC_%04d.jpg -vcodec libx264 -crf 25 -pix_fmt yuv420p ../video_lowres.mp4


This had no effect and still produced 6000x4000 video. So instead, I tried this parameter :
scale=1500:1000The full command I ran :

ffmpeg -r 60 scale=1500:1000 -start_number 3790 -i DSC_%04d.jpg -vcodec libx264 -crf 25 -pix_fmt yuv420p ../video_lowres.mp4


But I got this error :


[NULL @ 000002ad897bd9c0] Unable to find a suitable output format for 'scale=1500:1000'
scale=1500:1000: Invalid argument


How can I create a downscaled video from photos using ffmpeg ?


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How to create video file using fs from react form ?
7 avril 2021, par KirasirisI'm developing a section in which I need to create a video from a form that I'm using in a React application ; the returned data that I get from said file is this :


File >
 lastModified: 1617759553928
 lastModifiedDate: Tue Apr 06 2021 20:39:13 GMT-0500 (Central Daylight Time) {}
 name: "Shinobi Sisters.mp4"
 path: "Shinobi Sisters.mp4"
 size: 2564227
 type: "video/mp4"
 webkitRelativePath: ""
 __proto__: File


I'm sending all of that to a function called
createDirectoryAndFile(path, file), which so far looks like this :

// CREATE VIDEO FILE
const dir = './temp';
const createDirectoryAndFile = async (inputPath, inputContent) => {
 if (!fs.existsSync(dir)) {
 fs.mkdir(dir, { recursive: true });
 }

 fs.writeFile(inputPath, inputContent, (err) => {
 if (err) {
 console.error('An error ocurred', err);
 } else {
 console.log('Your file has been made');
 }
 });
};


It gets to the point in which is able to create the 'temp' directory but fails to place the video within it. Is there a reason for this ?


I need this because this is the starting point for me to work in my application. I'm trying to upload a video, create a second copy of it with a watermark(thanks to ffmpeg and ffprobe) and then finally upload it to AWS S3.


From my understanding all of that is only possible if the video is actually exists(not in memory).


Do you have guys have any idea ? Yes, I already installed
ffmpegandffprobe

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The FFmpeg just show the number form the input text (no characters , just numbers) error=13, Permission denied
14 avril 2021, par gejivi2011I was trying to use FFmpeg to create a video form gif and audio, on Android 10, doesn't work
The code is working fine on android 9 and below, and not work 10 and above
the Cmd, as I mentioned it is work so good on android 9 and below


String[] cmd = new String[24];
 cmd[0] = "-i";
 cmd[1] = audio.getPath();
 cmd[2] = "-ignore_loop";
 cmd[3] = "0";
 cmd[4] = "-i";
 cmd[5] = image_path;
 cmd[6] = "-vf";
 cmd[7] = "scale=trunc(iw/2)*2:trunc(ih/2)*2";
 cmd[8] = "-filter:v";
 cmd[9] = ayat_drawer + qara_draw;
 cmd[10] = "-vcodec";
 cmd[11] = "libx264";
 cmd[12] = "-pix_fmt";
 cmd[13] = "yuv420p";
 cmd[14] = "-r";
 cmd[15] = "25";
 cmd[16] = "-preset";
 cmd[17] = "ultrafast";
 cmd[18] = "-c:a";
 cmd[19] = "aac";
 cmd[20] = "-b:a";
 cmd[21] = "128k";
 cmd[22] = "-shortest";
 cmd[23] = outputLocation.getPath();


The Java code :


FFmpeg mFFmpeg = FFmpeg.getInstance(context);
 try {
 mFFmpeg.execute(cmd, new ExecuteBinaryResponseHandler() {
 @Override
 public void onProgress(String message) {
 super.onProgress(message);
 callback.onProgress(message);
 }

 @Override
 public void onSuccess(String message) {
 super.onSuccess(message);
 Utils.refreshGallery(outputLocation.getPath(), context);
 callback.onSuccess(outputLocation, "video");
 }

 @Override
 public void onFailure(String message) {
 super.onFailure(message);
 if (outputLocation.exists()) {
 outputLocation.delete();
 }
 callback.onFailure(new IOException(message));
 }

 @Override
 public void onStart() {
 Log.d("TAG", "<ffmpeg>Started command : mFFmpeg " + java.util.Arrays.toString(cmd));
 }

 @Override
 public void onFinish() {
 Log.d("TAG", "<ffmpeg>Finished command : mFFmpeg " + java.util.Arrays.toString(cmd));
 super.onFinish();
 callback.onFinish();
 }
 });
 } catch (FFmpegCommandAlreadyRunningException e) {
 Log.e("MAS" , e.getMessage());
 e.printStackTrace();
 }
</ffmpeg></ffmpeg>

I think that because FFmpeg using Asynctask and it is deprecated


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