Recherche avancée

Sur d’autres sites (5680)

• FFmpeg works on command line but not working on PHP script [on hold]

  6 août 2014, par burakcakirel

  Here is the screenshot to compare the results of command line output and PHP script output.

  http://screencast.com/t/e8Cdmr6aQ

  

  It works when ffmpeg command runs on command line, but it doesn’t work when using exec() command in php script. Any solution ?

  Also, the following screenshot shows that all about ffmpeg on the server :

  http://screencast.com/t/N9TnOORJkx

  

  I’ve tried /opt/mct/bin/ffmpeg and /usr/local/bin/ffmpeg. Nothing works on php script.

  safe_mode => OFF
  
  
  
  FFmpeg paths => 755

  EDIT : FFmpeg command already exists in the screenshot. Anyway here are the commands which none of them don’t work :

  /root/bin/ffmpeg -y -i Intro1.mp4 -strict -2 -s 640x480 Intro1_mp4.mp4 2>&1
  
  
  
  /opt/mct/bin/ffmpeg -y -i Intro1.mp4 -strict -2 -s 640x480 Intro1_mp4.mp4 2>&1
  
  
  
  /usr/local/bin/ffmpeg -y -i Intro1.mp4 -strict -2 -s 640x480 Intro1_mp4.mp4 2>&1

• Windows CMD Batch Script FFmpeg

  1er mars 2021, par Tobias

  I have created a batch file (.bat) that uses FFmpeg to transcode various videos (with *.mov or *.mp4 file name extension) from an input folder to an output folder (with extension *.mkv) as batch process (Windows 10 environment).
File names (without extension) from the input folder should be copied to the newly created output file names (that have the new file extension *.mkv).

  


  @echo off

set CMD=ffmpeg -c:v ffv1 -level 3 -g 1 -coder 1 -context 1 -pix_fmt + -slices 24 -slicecrc 1 -report -c:a pcm_s24le

FOR /R input_folder %%G IN (*.mov,*.mp4) DO (
   echo %%G
   call set outputfile=%%~nG%.mkv
   call set inputfile=%%~nG%%~xG
   echo %CMD% -y output_folder/%outputfile% -i %inputfile%
)


  


  But this script does not work as expected, i.e. nothing happens.
Do you perhaps have an idea how to fix this ?
Thanks in advance !

  


• Parsing Values To Shell Bash Script

  30 septembre 2014, par user1503606

  I am trying to make a simple bash script for a command so i can make it reusable for me the command has been taken from another post to convert videos with ffmpeg then upload.

  Here is what i have so far.

  #!/bin/bash
  
  MOVIES=$1
  
  EXT=$2
  
  BUCKET=$3
  
  find "$MOVIES" -name "*.$EXT" -exec sh -c 'ffmpeg -i "$0" -c:v libx264 -crf 22 -c:a libfaac -movflags faststart "${0%%.mov}.mp4" && s3cmd put "${0%%.mov}.mp4" "$BUCKET""$(basename "${0%%.mov}.mp4")"' {} \;
  
  exit;

  I am having issues with the third var if i run it like this.

  sh batch.sh ~/Documents/screengrabs/ mov s3://bucket/

  I am getting a error it encodes properly.

  ERROR: Parameter problem: Destination must be S3Uri. Got: file://49A22352-9F41-48B9-BF97-610CBF699025-630-0000055828D0D55F.mp4

  This means it is not parsing the $3 parameter $BUCKET properly.

  Any help this is my first bash script attempt.

  Thanks

  Update still not working

  #!/bin/bash
  
  MOVIES="$1"
  
  EXT="$2"
  
  BUCKET="$3"
  
  
  
  find "$MOVIES" -name "*.${EXT}" -exec sh -c 'ffmpeg -i "$0" -c:v libx264 -crf 22 -c:a libfaac -movflags faststart "${0%%.mov}.mp4" && s3cmd put "${0%%.mov}.mp4" "${BUCKET}/sam.mp4"' {} \;
  
  
  
  exit;

  WORKING

  #!/bin/bash
  
  MOVIES=$1
  
  EXT=$2
  
  export BUCKET=$3
  
  find "$MOVIES" -name "*.$EXT" -exec sh -c 'ffmpeg -i "$0" -c:v libx264 -crf 22 -c:a libfaac -movflags faststart "${0%%.mov}.mp4" && s3cmd put "${0%%.mov}.mp4" "$BUCKET""$(basename "${0%%.mov}.mp4")"' {} \;
  
  exit;