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    13 avril 2011

    Unfortunately a software is never perfect.
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Sur d’autres sites (7650)

  • C# FFMPEG - How to get extracted frames without save in file system

    4 janvier 2023, par kadam

    I need to process frames from video and live stream without saving into file system.

    


    C# I am trying using below code, but not getting frames

    


    Process proc = new Process();
            proc.StartInfo.FileName = @"E:\ffmpeg\bin\ffmpeg.exe";
            proc.StartInfo.Arguments = String.Format(@"-i E:\ffmpeg\bin\video.mp4 -f rawvideo pipe:1");
            proc.StartInfo.UseShellExecute = false;
            proc.StartInfo.RedirectStandardOutput = true;
            proc.Start();
proc.OutputDataReceived += (sender, args) => DataReceived(args);
            proc.ErrorDataReceived += (sender, args) => DataReceived(args);


    


    I can get frames in nodejs successfully using below code

    


    
const spawnProcess = require('child_process').spawn
    ffmpeg = spawnProcess('E:\\ffmpeg\\bin\\ffmpeg.exe', [
      '-i', 'rtsp://username:password@192.168.6.37/ch1/main/sub-stream',
      '-vcodec', 'mjpeg','-vf','fps=2',
      '-f', 'rawvideo',
      //'-s', HW, // size of one frame
      'pipe:1'
  ]);
      ffmpeg.stderr.pipe(logStream);
      let frames = [];
      ffmpeg.stdout.pipe(new ExtractFrames("FFD8FF")).on('data', (data) => {
        var fName=new Date().getTime()+".png";
        (
          async () => await ProcessFrame(Buffer.from(data).toString('base64'))
        )();
      })


    


    Same thing await ProcessFrame(Buffer.from(data).toString('base64')) I want in C#

    


  • Node.js Stream Mp3 to http without having to save file

    10 janvier 2019, par user2758113

    I am trying to stream just audio from a youtube link straight to http with node.js.

    My code looks like this, I am using express 4.0.

    var express = require('express');
    var router = express.Router();
    var ytdl = require('ytdl');
    var ffmpeg = require('fluent-ffmpeg');
    var fs = require('fs');

    router.get('/', function(req, res) {

     var url = 'https://www.youtube.com/watch?v=GgcHlZsOgQo';
     var video = ytdl(url)

     res.set({
         "Content-Type": "audio/mpeg"
     })

     new ffmpeg({source: video})
         .toFormat('mp3')
         .writeToStream(res, function(data, err) {
           if (err) console.log(err)
         })

    });

    module.exports = router;

    Now, I’m able to stream the video’s audio to the response if I save the file then pipe it to the response, but I’d rather try to figure out some way to go from downloading to ffmpeg to response.

    Not sure if this is possible. The main goal is to keep it as light weight as possible, and not have to read from files.

    I’ve seen this code which is essentially what I’d like to do minus the saving to a file part.

    part of the error

  • Node.js Stream Mp3 to http without having to save file

    21 août 2016, par user2758113

    I am trying to stream just audio from a youtube link straight to http with node.js.

    My code looks like this, I am using express 4.0.

    var express = require('express');
    var router = express.Router();
    var ytdl = require('ytdl');
    var ffmpeg = require('fluent-ffmpeg');
    var fs = require('fs');

    router.get('/', function(req, res) {

     var url = 'https://www.youtube.com/watch?v=GgcHlZsOgQo';
     var video = ytdl(url)

     res.set({
         "Content-Type": "audio/mpeg"
     })

     new ffmpeg({source: video})
         .toFormat('mp3')
         .writeToStream(res, function(data, err) {
           if (err) console.log(err)
         })

    });

    module.exports = router;

    Now, I’m able to stream the video’s audio to the response if I save the file then pipe it to the response, but I’d rather try to figure out some way to go from downloading to ffmpeg to response.

    Not sure if this is possible. The main goal is to keep it as light weight as possible, and not have to read from files.

    I’ve seen this code which is essentially what I’d like to do minus the saving to a file part.

    part of the error