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  • Les autorisations surchargées par les plugins

    27 avril 2010, par

    Mediaspip core
    autoriser_auteur_modifier() afin que les visiteurs soient capables de modifier leurs informations sur la page d’auteurs

  • Personnaliser les catégories

    21 juin 2013, par

    Formulaire de création d’une catégorie
    Pour ceux qui connaissent bien SPIP, une catégorie peut être assimilée à une rubrique.
    Dans le cas d’un document de type catégorie, les champs proposés par défaut sont : Texte
    On peut modifier ce formulaire dans la partie :
    Administration > Configuration des masques de formulaire.
    Dans le cas d’un document de type média, les champs non affichés par défaut sont : Descriptif rapide
    Par ailleurs, c’est dans cette partie configuration qu’on peut indiquer le (...)

  • Other interesting software

    13 avril 2011, par

    We don’t claim to be the only ones doing what we do ... and especially not to assert claims to be the best either ... What we do, we just try to do it well and getting better ...
    The following list represents softwares that tend to be more or less as MediaSPIP or that MediaSPIP tries more or less to do the same, whatever ...
    We don’t know them, we didn’t try them, but you can take a peek.
    Videopress
    Website : http://videopress.com/
    License : GNU/GPL v2
    Source code : (...)

Sur d’autres sites (8273)

  • How to merge videos (without audio) and add audio to them after merging in single line command ? [on hold]

    25 juillet 2019, par Kartik Chhajed

    I want to merge three videos and then after I want to replace/rewrite the audio streams. Basically, there are 4 files, three are .mp4 and one mp3.

    I have done this explicitly with two-line code and it’s working.

    The two line code :

    ffmpeg -i 20190722_115754.mp4 -i 20190722_114403.mp4 -i 20190722_110008.mp4 -filter_complex "[0:v:0] [1:v:0] [2:v:0] concat=n=3:v=1 [v]" -map "[v]" output_video_1.mp4
    ffmpeg -i output_video_1.mp4 -i audio.mp3 -c copy -map 0:v:0 -map 1:a:0 -shortest output_video_2.mp4

    But I want one-liner,
    The one-liner which I have tried are :

    ffmpeg -i 20190722_115754.mp4 -i 20190722_114403.mp4 -i 20190722_110008.mp4 -filter_complex "[0:v:0] [1:v:0] [2:v:0] concat=n=3:v=1 [v]" -i audio.mp3 -c copy -map "[v]" -map 3:a:0 -shortest output_video_3.mp4

    And

    ffmpeg -i 20190722_115754.mp4 -i 20190722_114403.mp4 -i 20190722_110008.mp4 -i audio.mp3 -filter_complex "[3:a:0] [0:v:0] [1:v:0] [2:v:0] concat=n=3:v=1 [v] [a]" -map "[v]" -map "[a]" output_video_3.mp4

    But, this will not work.

    I want to reduce to one line code.

  • ffmpeg : take bsf arguments from the command line

    29 novembre 2014, par Christophe Gisquet
    ffmpeg : take bsf arguments from the command line
    

    The format is now :
    - bsf:X filter1[=opt1=str1/opt2=str2],filter2
    ie the parameters are appended after the filter name using ’=’. As ’,’
    has been reserved already for the list of filters, ’/’ is just an
    example of token separation for now, but that could become part of the
    API to avoid each bsf using its own tokenization.

    The proper solution would be using AVOption, but this is overkill for now.

    Signed-off-by : Michael Niedermayer <michaelni@gmx.at>

    • [DH] doc/bitstream_filters.texi
    • [DH] ffmpeg.c
    • [DH] ffmpeg.h
    • [DH] ffmpeg_opt.c
  • How to use output of FFMPEG as command line argument to an executable

    22 février 2017, par pku

    I have a .wmv file which I want to convert to .wav file and I am using ffmpeg for the same, the command is as follows :

    ffmpeg -i file.wmv -ar 8000 -sample_fmt s16 -f wav pipe:1

    the pipe:1 outputs the output wave file in STDOUT. I want to capture that wave file from STDOUT and pass it as a command line argument to my executable called foo. I want to do the conversion from wmv to wav on the fly rather than saving the .wav file.
    Things I have tried are as follows but none of them seem to work :

    ./foo $(ffmpeg -i file.wmv -ar 8000 -sample_fmt s16 -f wav pipe:1)

    ./foo $(&lt;(ffmpeg -i file.wmv -ar 8000 -sample_fmt s16 -f wav pipe:1))

    ffmpeg -i file.wmv -ar 8000 -sample_fmt s16 -f wav pipe:1 | xargs ./foo

    ffmpeg -i file.wmv -ar 8000 -sample_fmt s16 -f wav - | ./foo -