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• System.Diagnostics.Process program keeps on running

  3 février 2016, par edotom

  I’m trying to convert some avi files into mkv using ffmpeg library from a commandline application. I made a method that allows me to do that :

  public bool convertAvitoMkv(string path, string sourceName, string destName)
  
      {
  
  
  
          bool returncode = false;
  
          try
  
          {
  
              string comando = string.Format("-i {0} -c:v libx264 -crf 19 -preset slow -c:a libfaac -b:a 192k -ac 2 {1}", string.Format("{0}\\{1}",path,sourceName), string.Format("{0}\\{1}",path,destName) + ".mkv");
  
              System.Diagnostics.Process process = new System.Diagnostics.Process();
  
              System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
  
              startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
  
              startInfo.FileName = "ffmpeg.exe";
  
              startInfo.WorkingDirectory = programPath;
  
              startInfo.CreateNoWindow = true;
  
              startInfo.Arguments = comando;
  
              process.StartInfo = startInfo;
  
              process.Start();
  
              while (!process.HasExited)
  
              {
  
                  process.Kill(); 
  
                  //continue hasta que termine la ejecucion
  
              }
  
  
  
              returncode = process.HasExited;
  
          }
  
          catch (Exception ex)
  
          {
  
  
  
          }
  
          return returncode;
  
      }

  the previous version did not have the while (!process.HasExited), but I added it because I noticed that there were a lot of instances of ffmpeg.exe running that I had to close by hand. How can I guarantee that every conversión is made and that every instance of ffmpeg is closed ?
  regards

• Getting return value of command inspite of sudo inside of php system

  21 avril 2016, par nithintou

  I’ve been trying for a few days to get the return value of a script that performs an ffmpeg recording in the server using php system() :

  system("/usr/bin/sudo /usr/bin/php /root/startrecord.php $userid", $retval);

  Tried exec() as well, but still can’t get the correct exit(n) code from the recording script to perform the next steps. I am guessing the return value i keep getting is from sudo and not the actual php script.

  Can you guys suggest any workarounds or tips as to what I may be doing wrong ?

• Revision 0b0eba728d : Add _dspr2 to local function names It avoids symbol conflicts between function

  31 juillet 2015, par Jingning Han

  Changed Paths :
   Modify /vp9/common/mips/dspr2/vp9_itrans16_dspr2.c

  
  
  Add _dspr2 to local function names

  It avoids symbol conflicts between function names of various
  implementation versions.

  Change-Id : Iad79ebcb8e289457801812a7745c8380b5b06a46