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• ffmpeg save highly quality video by using rtsp link [closed]

  22 août 2023, par Shivam Singh

  I'm trying to download good quality of video from the camera stream by using ffmpeg

  


  ffmpeg -i rtsp://admin:admin@123@117.216.143.251:556 -r 15 /home/Documents/Yolo/yolo/251.avi


  


  How to download good quality of video by using ffmpeg ?

  


• Convert video into mp3 format using ffmpeg in nodejs and angular and then save converted audio into the database(mongodb)

  6 septembre 2021, par Amir Shahzad

  This is nodejs server side file

  


  const express = require('express');
const ffmpeg  = require('fluent-ffmpeg');
const fileUpload = require('express-fileupload');
const mongoose = require('mongoose');
const cors   = require('cors')
const app = express();
const Video = require('./models/video');
mongoose.connect('mongodb://localhost:27017/YoutubeApp', {
    useNewUrlParser: true,
    useUnifiedTopology: true,
});
const db = mongoose.connection;
db.on('error', console.error.bind(console, 'connection error'));
db.once('open', () => {
   console.log('Data Base Connected Successfully!');
});

app.use(fileUpload({
   useTempFiles: true,
   tempFileDir: 'temp/'
}));
app.use(express.json());
app.use(express.urlencoded({ extended: true }));
app.use(cors({ origin: 'http://localhost:4200' }));


ffmpeg.setFfmpegPath('/usr/bin/ffmpeg');

app.post('/mp4tomp3', (req, res) => {
  convertdata = req.body;
  console.log('path of innput is', req.body);
  function convert(input, output, callback) {
     ffmpeg(input)
         .output(output)
         .on('end', function() {                    
             console.log('conversion ended');
             callback(null);
           }).on('error', function(err){
              console.log('error: ', err.code, err.msg);
              callback(err);
           }).run();
      }
     convert(convertdata, './temp/output.mp3', function(err){
        if(!err) {
          console.log('conversion complete');

 
     }
 })

 app.listen(3000, () => {
    console.log('Server Start On Port 3000')
 })


  


  In Convert function i not know how i can get input by the user i'm new in angular Please anyone can solve this out thanks in advance

  


  This is video model file

  


  const mongoose = require("mongoose");
const Schema = mongoose.Schema;

const videoSchema = new Schema({
    mp4: String,
});
module.exports = mongoose.model("Videos", videoSchema);


  


  **This is Typescript code in angular client side that handle user input and select video **

  


  import { ThrowStmt } from '@angular/compiler';
import { Component, OnInit } from '@angular/core';
import { FormBuilder, FormGroup, Validators } from '@angular/forms';
import { VideoConversionService } from 'src/services/video-conversion.service';

@Component({
  selector: 'app-root',
  templateUrl: './app.component.html',
  styleUrls: ['./app.component.css']
})
export class AppComponent implements OnInit {

   submitted =false;
   form! : FormGroup
   data:any

   constructor(private formBuilder: FormBuilder,
       private videoService: VideoConversionService){}

   creatForm(){
    this.form = this.formBuilder.group({
    mp4: ['', Validators.required],
  });
  }
   ngOnInit(): void {
   this.creatForm();

  }


  convertVideo(){
    this.submitted = true
    this.videoService.conversion(this.form.value).subscribe(res => {
    this.data = res;
 })
 }

 }


  


  I do not know how to create logic to do that (convert video into audio using angular framework)

  


  This is app.component.html file where i want to get video from the user using input field

  


  <div class="container">&#xA;   <h1>Video Proccessing App</h1>&#xA;   <form>&#xA;     <input type="file" formcontrolname="mp4" />&#xA;     <input type="submit" value="Convert" />&#xA;  </form>&#xA;</div>&#xA;

  


  


  But my code is not working and video is not converting into audio

  


  This is my video service file where i calling nodejs api to perform the task

  


  import { Injectable } from '@angular/core';
import { HttpClient  } from '@angular/common/http';
@Injectable({
   providedIn: 'root'
})
export class VideoConversionService {

constructor(private httpClient: HttpClient) { }

conversion(data: any){
   return this.httpClient.post('http://localhost:3000/mp4tomp3', data)
}
}


  


  Please anyone can solve my problem Thanks in advance

  


• pyav - cannot save stream as mono

  3 août 2022, par Zvika

  I'm trying to use pyav to convert arbitrary audio file to a low quality, mono, wave file.

  


  I almost managed to do it, but it's stereo, and I couldn't find how to make it mono. Furthermore, I think I made some mistake here, as I had to repeat the rate in the output_container.add_stream and in the AudioResampler - it seems redundant, and I can't understand what would happen if those numbers won't match.

  


  My code is :

  


      import av
    
    input_file = 'some.mp3'
    output_file = 'new.wav'
    
    rate = 22000
    
    output_container = av.open(output_file, 'w')

    # can I tell `output_stream` to just use `resampler`'s info?
    # or, if not, how can I tell it to have only 1 channel?
    output_stream = output_container.add_stream('pcm_u8', rate)  
    
    resampler = av.audio.resampler.AudioResampler('u8p', 'mono', rate)
    
    input_container = av.open(input_file)
    for frame in input_container.decode(audio=0):
        out_frames = resampler.resample(frame)
        for out_frame in out_frames:
            for packet in output_stream.encode(out_frame):
                output_container.mux(packet)
    output_container.close()


  


  And not related to my main question, but any comments regarding my code, or pointing out mistakes, are welcomed. I hardly could find usage examples to use a reference, and PyAV API documentation isn't very detailed...