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• How do I pass a pipe to ffmpeg ?

  6 novembre 2022, par m_j_alkarkhi

  I want to send a couple of images to ffmpeg and output a video

  


  I have tried to use something similar to this which always seems to finish but when I check the output, it always returns an empty 48b file

  


  I have tried changing the order of the flags but nothing seems to work

  


  Here is my code

  


  using System.Diagnostics;
using SkiaSharp;

Process process = new Process();
process.StartInfo.FileName = @"ffmpeg";
process.StartInfo.Arguments = "-f image2pipe -r 30 -i - /home/user/Videos/test33.mp4";
process.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardInput = true;
process.StartInfo.RedirectStandardOutput = true;
        
process.Start();

for (int i = 0; i < 300; i++)
{
    using var ms = new MemoryStream();
    SKImageInfo imageInfo = new SKImageInfo(1280, 720, SKColorType.Rgba8888);
    using SKSurface surface = SKSurface.Create(imageInfo);
    SKCanvas canvas = surface.Canvas;
    canvas.Clear(SKColor.Parse("#ffffff"));
    using SKImage image = surface.Snapshot();
    using SKData data = image.Encode(SKEncodedImageFormat.Png, 80);
    data.SaveTo(ms);
    ms.WriteTo(process.StandardInput.BaseStream);
}


  


• How to Bulk Speed UP and Crop Videos FFMPEG

  6 septembre 2023, par Usemo Shank

  I have videos in (input) folder that is located on the root of the script, I also have output folder on the root, The input folder has several videos that i want to speed up in bulk by 1.1 percent, I also want to cropt the videos by 90 percent (Meaning 90 Percent of original video is visible).

  


  I have a code that does not function well. Here is the code I have

  


   import os
import subprocess

# Define input and output directories
input_folder = "input"
output_folder = "output"

# Create the output directory if it doesn't exist
if not os.path.exists(output_folder):
    os.makedirs(output_folder)

# List all video files in the input directory
input_files = [f for f in os.listdir(input_folder) if f.endswith(('.mp4', '.avi', '.mkv'))]

# Speed up and crop each video
for input_file in input_files:
    input_path = os.path.join(input_folder, input_file)
    output_file = os.path.splitext(input_file)[0] + "_speed_crop.mp4"
    output_path = os.path.join(output_folder, output_file)

    # FFmpeg command to speed up video by 1.1x and crop to 90%
    ffmpeg_command = [
        "ffmpeg",
        "-i", input_path,
        "-vf", "setpts=1.1*PTS,crop=in_w*0.9:in_h*0.9",
        "-c:v", "libx264",
        "-crf", "20",
        "-c:a", "aac",
        "-strict", "experimental",
        output_path
    ]

    # Run FFmpeg command
    subprocess.run(ffmpeg_command)

print("Conversion complete.")


  


• cronjob to play files in a folder with ffmpeg causes delay between songs. how to avoid ?

  21 juillet 2014, par Andy

  I have a cron set up to check for a specific stream and if its not playing(usually means that file is over) it will randomly select other file.

  The command :
  /root/bin/ffmpeg -re -i $(ls /usr/btv/btvconcerts/*.mp4 | shuf -n 1) -vcodec copy -preset superfast -acodec copy -ar 44100 -ab 32k -f flv OUTPUT

  The problem I have is that the cron is running every 1 minute and so there could be a delay between the streaming files for up to 1 min + the time it launches etc

  Is there a command i could use just to constantly loop through the files without crontab ?