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• Error : Unable to extract uploader id - Youtube, Discord.py

  22 juillet 2024, par nikita goncharov

  I have a very powerful bot in discord (discord.py, PYTHON) and it can play music in voice channels. It gets the music from youtube (youtube_dl). It worked perfectly before but now it doesn't want to work with any video.
I tried updating youtube_dl but it still doesn't work
I searched everywhere but I still can't find a answer that might help me.

  


  This is the Error : Error: Unable to extract uploader id

  


  After and before the error log there is no more information.
Can anyone help ?

  


  I will leave some of the code that I use for my bot...
The youtube setup settings :

  


  youtube_dl.utils.bug_reports_message = lambda: ''


ytdl_format_options = {
    'format': 'bestaudio/best',
    'outtmpl': '%(extractor)s-%(id)s-%(title)s.%(ext)s',
    'restrictfilenames': True,
    'noplaylist': True,
    'nocheckcertificate': True,
    'ignoreerrors': False,
    'logtostderr': False,
    'quiet': True,
    'no_warnings': True,
    'default_search': 'auto',
    'source_address': '0.0.0.0',  # bind to ipv4 since ipv6 addresses cause issues sometimes
}

ffmpeg_options = {
    'options': '-vn',
}

ytdl = youtube_dl.YoutubeDL(ytdl_format_options)


class YTDLSource(discord.PCMVolumeTransformer):
    def __init__(self, source, *, data, volume=0.5):
        super().__init__(source, volume)

        self.data = data

        self.title = data.get('title')
        self.url = data.get('url')
        self.duration = data.get('duration')
        self.image = data.get("thumbnails")[0]["url"]
    @classmethod
    async def from_url(cls, url, *, loop=None, stream=False):
        loop = loop or asyncio.get_event_loop()
        data = await loop.run_in_executor(None, lambda: ytdl.extract_info(url, download=not stream))
        #print(data)

        if 'entries' in data:
            # take first item from a playlist
            data = data['entries'][0]
        #print(data["thumbnails"][0]["url"])
        #print(data["duration"])
        filename = data['url'] if stream else ytdl.prepare_filename(data)
        return cls(discord.FFmpegPCMAudio(filename, **ffmpeg_options), data=data)



  


  Approximately the command to run the audio (from my bot) :

  


  sessionChanel = message.author.voice.channel
await sessionChannel.connect()
url = matched.group(1)
player = await YTDLSource.from_url(url, loop=client.loop, stream=True)
sessionChannel.guild.voice_client.play(player, after=lambda e: print(
                                       f'Player error: {e}') if e else None)


  


• Do avcodec_receive_frame and avcodec_send_packet block / how to design ffmpeg decoding loop ?

  12 octobre 2020, par Paprika

  I'm thinking about how to design a loop that reads frames from internet, feed to ffmpeg decoder and then receive from ffmpeg to send to a render.

  


  Take this pseudocode loop in consideration :

  


  while true {
    auto packet = receive_packet_from_network();
    avcodec_send_packet(packet);
    auto frame = alloc_empty_frame();
    int r = avcodec_receive_frame(&frame);
    if (r==0) {
        send_to_render(frame);
    }
}


  


  do avcodec_send_packet or avcodec_receive_frame block or ffmpeg has an internal thread ? I'm concerned about this loop because it waits for packets from network, so it has some delay. I'd like to do something like this instead :

  


  //thread 1
while true {
    auto packet = receive_packet_from_network();
    avcodec_send_packet(packet);
}
//thread 2
while true {
    auto frame = alloc_empty_frame();
    int r = avcodec_receive_frame(&frame);
    if (r==0) {
        send_to_render(frame);
    }
}


  


  however, now, if avcodec_receive_frame does not block, then this loop would run too fast, millions of times per second.

  


  So, how should I design the send/receive of packets in ffmpeg in the most efficient way ? I don't want to spend cpu cycles like in the thread2 loop.

  


• FFMPEG C# Winforms Output to Textbox

  21 janvier 2016, par user1700974

  Trying to write a video compression app using Windows Forms, I can get the file to compress ok, but I’m looking to show the process to something like a textbox ?

  At the minute the program doesn’t have a progress, so you don’t know if its complete or not, is it possible to output with FFMPEG is doing to a textbox ?

  This is my code, when it runs nothing is shown in the textbox :

  string ffmpeg = @"c:\test\ffmpeg.exe";
  
              ProcessStartInfo psi = new ProcessStartInfo(ffmpeg);
  
              psi.UseShellExecute = false;
  
              psi.CreateNoWindow = true;
  
  
  
              psi.RedirectStandardOutput = true;
  
  
  
              psi.Arguments = "-i c:\\test\\small.mp4 -s 480x272 c:\\test\\compressed.mp4";
  
  
  
              var proc = Process.Start(psi);
  
  
  
              string s = proc.StandardOutput.ReadToEnd();
  
  
  
              textBox1.Text = s;

  Do i need to pass something else into the ProcessStartInfo section ?