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  • Keeping control of your media in your hands

    13 avril 2011, par

    The vocabulary used on this site and around MediaSPIP in general, aims to avoid reference to Web 2.0 and the companies that profit from media-sharing.
    While using MediaSPIP, you are invited to avoid using words like "Brand", "Cloud" and "Market".
    MediaSPIP is designed to facilitate the sharing of creative media online, while allowing authors to retain complete control of their work.
    MediaSPIP aims to be accessible to as many people as possible and development is based on expanding the (...)

  • Participer à sa traduction

    10 avril 2011

    Vous pouvez nous aider à améliorer les locutions utilisées dans le logiciel ou à traduire celui-ci dans n’importe qu’elle nouvelle langue permettant sa diffusion à de nouvelles communautés linguistiques.
    Pour ce faire, on utilise l’interface de traduction de SPIP où l’ensemble des modules de langue de MediaSPIP sont à disposition. ll vous suffit de vous inscrire sur la liste de discussion des traducteurs pour demander plus d’informations.
    Actuellement MediaSPIP n’est disponible qu’en français et (...)

  • Websites made ​​with MediaSPIP

    2 mai 2011, par

    This page lists some websites based on MediaSPIP.

Sur d’autres sites (11563)

  • FFMPEG linux how to get the total time duration of a folder containing videos ?

    3 octobre 2015, par Andrea Turco

    i need to get the total count of video times in a folder

    I need to generate a file .txt that export just the total time of the videos in the folder in the format :

    HH:MM:SS

    Actually with this script i get just the duration of single files splitted..i need just single output in the file video_times.txt with the total duration.

    videos=( "/home/videos")
    default_ext=( mp4 avi )
    dump_file=./video_times.txt

    # parameters or default values?
    (( $#==0 )) && ext=( "${default_ext[@]}" ) || ext=( "$@" )
    echo "locations: ${videos[@]/$HOME/~}"
    echo "extensions: ${ext[@]}"

    for(( i=0; i<${#ext[@]}; i++ ))
    do
     (( i>0 )) && find_params+=( -o )
     find_params+=( -iname '*.'${ext[$i]} )
    done
    find_params=( '(' "${find_params[@]}" ')' )

    rm "$dump_file" 2>/dev/null

    while IFS= read -rd '' f
    do
     echo "$(( ++n )): $f"
     # time in original HH:MM:SS.ms format and in SSSSSS.ms
     ffmpeg -i "$f" 2>&1 | awk '/Duration:/ {split($2, t, ":|,"); print $2 t[1]*3600+t[2]*60+t[3]; }' >> "$dump_file"
    done < <( find "${videos[@]}" "${find_params[@]}" -print0 )

    awk -F, '    {
                  total=$2;
            #  printing numbers during work
            #      printf("%+10.2f\t(%10.2f)\n", $2, total );
                }
            END {
            #      print "-----------------------------";
                  printf( "%.2f seconds in %d files\n", total, NR );
                  h=total/3600; total%=3600;
                  m=total/60; total%=60;
                  printf( "%02d:%02d:%s\n", h, m, total )
                }' "$dump_file"
  • How to merge two videos using ffmpeg Android

    12 août 2021, par Usama Shakeel

    I have two videos which I want to merge. Both have same resolution. The second video does not have any audio

    


    ffmpeg -i test.mp4 -i picture.mp4 -filter_complex "[0:v] [0:a] [1:v] [1:a] concat=n=1:v=2:a=1 [v] [a]" -map "[vv]" -map "[aa]" mergedVideo.mp4

    


    this is the command that I am using but I am getting the following error
Stream specifier ':a' in filtergraph description [0:v] [0:a] [1:v] [1:a] concat=n=2:v=2:a=1 [v] [a] matches no streams.

    


    I am not very familiar with ffmpeg commands but I guess I am giving some wrong -filter complex values

    


  • Vertically or horizontally stack (mosaic) several videos using ffmpeg ? [closed]

    2 septembre 2021, par Joseph Turian

    I have two videos of the same exact length, and I would like to use ffmpeg to stack them into one video file.

    



    How can I do this ?