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• Capturing terminal output into pandas dataframe without creating external text file

  4 septembre 2024, par tavalendo

  I am using ffmpeg's extract_mvs file to generate some text information. I would use a command like this in the terminal :

  



  /extract_mvs input.mp4 > output.txt


  



  I would like to use this command with Popen or other subprocess in python such that instead of output.txt, the data is passed straight to a pandas data frame without actually generating the text file.

  



  The idea is to automate this multiple times, so, I am trying to avoid many .txt files from being generated and thus having to open() them one by one.

  



  I thought of something like this :

  



  import subprocess
cmd = ['./extract_mvs', 'input.mp4']
a = subprocess.Popen(cmd, stdout=subprocess.PIPE)
df = pd.read_csv(a.communicate()[0], sep=',')


  



  But then I get an error : OSError: Expected file path name or file-like object, got <class> type</class>

  



  Can it be fixed and extended so as to read straight from subprocess to pandas ?

  


• Debian ffmpeg working in terminal but not in php

  30 octobre 2013, par user2938660

  I reinstalled ffmpeg on debian and php exec doesn't work for me anymore when called from php. I'm using :

  if ($success_msg) 
  
  {
  
      $tmp_parts = explode('.', $file['name']);
  
      $ext = array_pop($tmp_parts);
  
      $ext = strtolower($ext);
  
      if($ext == "avi" && $convert_avi == true)
  
      {
  
          $convert_source = _VIDEOS_DIR_PATH.$new_name;
  
          $conv_name = substr(md5($file['name'].rand(1,888)), 2, 10).".mp4";
  
          //$conv_name2 = substr(md5($file['name'].rand(1,888)), 2, 10).".mp4";
  
          $converted_file  = _VIDEOS_DIR_PATH.$conv_name;
  
          //$fastarted_file  = _VIDEOS_DIR_PATH.$conv_name2;
  
          $ffmpeg_command = 'ffmpeg -i '.$convert_source.' -r 20 -g 40 -acodec libfaac -ar 44100 -ab 96k -vcodec libx264 -sameq '.$converted_file;
  
          //$faststart_command = "qt-faststart ".$converted_file." ".$fastarted_file;
  
          shell_exec($ffmpeg_command);
  
          unlink($convert_source);
  
          //shell_exec($faststart_command);
  
          $sql = "UPDATE pm_temp SET url = '".$conv_name."' WHERE url = '".$new_name."' LIMIT 1";
  
          $result = @mysql_query($sql);
  
  }
  
  echo $success_msg;

  this code to convert videos and ffmpeg output is :

  root@1tb:~# ffmpeg -version
  
  ffmpeg version git-2013-10-28-f1f0b01
  
  built on Oct 29 2013 02:05:45 with gcc 4.4.5 (Debian 4.4.5-8)
  
  configuration: --enable-gpl --enable-libfaac --enable-libmp3lame --enable-libopencore-amrnb --enable-libopencore-amrwb --enable-librtmp --enable-libtheora --enable-libvorbis --enable-libvpx --enable-libx264 --enable-nonfree --enable-version3 --enable-x11grab
  
  libavutil      52. 48.100 / 52. 48.100
  
  libavcodec     55. 39.100 / 55. 39.100
  
  libavformat    55. 19.104 / 55. 19.104
  
  libavdevice    55.  5.100 / 55.  5.100
  
  libavfilter     3. 90.100 /  3. 90.100
  
  libswscale      2.  5.101 /  2.  5.101
  
  libswresample   0. 17.104 /  0. 17.104
  
  libpostproc    52.  3.100 / 52.  3.100
  
  root@1tb:~#

  in terminal it works fine just via php not im sure this is server problem and exec is enabled.

• How do I use ffprobe in Terminal ?

  9 avril 2020, par Westicle

  When I use ffmpeg I use it like this :

  



  ./ffmpeg -ss 00:30:00 -i inputvideo.mp4 -t 00:00:20 -c:v copy -c:a copy outputvideo.mp4


  



  So how to I use ffprobe ? I've tried this but I can't get it to work :

  



  ./ffmpeg ffprobe -v error -show_frames inputvideo.mp4