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• I tried programming a discord bot for music, it joins the channel, it apparently "speaks" but i can't hear anything

  2 avril 2020, par borax

  I tried to code it alone, but I got the same problem, then I copied the code from https://gabrieltanner.org/blog/dicord-music-bot and it persists. I have downloaded FFmpeg, but I still think the problem lies there. Any suggestions ? (it's my first time here, I don't know how much of the code is relevant, also, i get this Error : FFmpeg/avconv not found !)

  



  const Discord = require('discord.js');
const client = new Discord.Client();

const ytdl = require("ytdl-core");

const token = 'REDACTED';

const prefix = '$';

var version = '1.1.2';

var servers = {};

const queue = new Map();

client.on('ready', () => {
    console.log('BOT is online');
})
client.once("ready", () => {
    console.log("Ready!");
  });

  client.once("reconnecting", () => {
    console.log("Reconnecting!");
  });

  client.once("disconnect", () => {
    console.log("Disconnect!");
  });

  client.on("message", async message => {
    if (message.author.bot) return;
    if (!message.content.startsWith(prefix)) return;

    const serverQueue = queue.get(message.guild.id);

    if (message.content.startsWith(`${prefix}play`)) {
      execute(message, serverQueue);
      return;
    } else if (message.content.startsWith(`${prefix}skip`)) {
      skip(message, serverQueue);
      return;
    } else if (message.content.startsWith(`${prefix}stop`)) {
      stop(message, serverQueue);
      return;
    } else {
      message.channel.send("You need to enter a valid command!");
    }
  });

  async function execute(message, serverQueue) {
    const args = message.content.split(" ");

    const voiceChannel = message.member.voice.channel;
    if (!voiceChannel)
      return message.channel.send(
        "You need to be in a voice channel to play music!"
      );
    const permissions = voiceChannel.permissionsFor(message.client.user);
    if (!permissions.has("CONNECT") || !permissions.has("SPEAK")) {
      return message.channel.send(
        "I need the permissions to join and speak in your voice channel!"
      );
    }

    const songInfo = await ytdl.getInfo(args[1]);
    const song = {
      title: songInfo.title,
      url: songInfo.video_url
    };

    if (!serverQueue) {
      const queueContruct = {
        textChannel: message.channel,
        voiceChannel: voiceChannel,
        connection: null,
        songs: [],
        volume: 5,
        playing: true
      };

      queue.set(message.guild.id, queueContruct);

      queueContruct.songs.push(song);

      try {
        var connection = await voiceChannel.join();
        queueContruct.connection = connection;
        play(message.guild, queueContruct.songs[0]);
      } catch (err) {
        console.log(err);
        queue.delete(message.guild.id);
        return message.channel.send(err);
      }
    } else {
      serverQueue.songs.push(song);
      return message.channel.send(`${song.title} has been added to the queue!`);
    }
  }

  function skip(message, serverQueue) {
    if (!message.member.voice.channel)
      return message.channel.send(
        "You have to be in a voice channel to stop the music!"
      );
    if (!serverQueue)
      return message.channel.send("There is no song that I could skip!");
    serverQueue.connection.dispatcher.end();
  }

  function stop(message, serverQueue) {
    if (!message.member.voice.channel)
      return message.channel.send(
        "You have to be in a voice channel to stop the music!"
      );
    serverQueue.songs = [];
    serverQueue.connection.dispatcher.end();
  }

  function play(guild, song) {
    const serverQueue = queue.get(guild.id);
    if (!song) {
      serverQueue.voiceChannel.leave();
      queue.delete(guild.id);
      return;
    }

    const dispatcher = serverQueue.connection
      .play(ytdl(song.url))
      .on("finish", () => {
        serverQueue.songs.shift();
        play(guild, serverQueue.songs[0]);
      })
      .on("error", error => console.error(error));
    dispatcher.setVolumeLogarithmic(serverQueue.volume / 5);
    serverQueue.textChannel.send(`Start playing: **${song.title}**`);
  }

client.login(token);


  


• FFMPEG how to use gdigrab to capture with codec h264 at mp4 extension ?

  12 décembre 2017, par Gomi Odabaşıoğlu

  I am trying to use FFMPEG console tools effectively. I successfully recorded a video but my mind is mixed since doc. has too many provided information. I have no idea which one to read. I use following option to capture a video :

  C:\Users\{--USERNAME HERE-}\Desktop\ffmpeg.exe -f gdigrab -show_region 1 -framerate 60 -i desktop C:\Users\{--USERNAME HERE-}\Desktop\out.mp4

  Here I used gdigrab that provided good quality and speed. I do not know if there are better options about screen recording for windows. Now, my purpose is to record a video with codec h264 at 60fps as mp4 file quality is 80 of 100 type. What should I do to acieve this ?

• How to include FFMPEG functions in android code

  4 janvier 2013, par TharakaNirmana

  My aim is to build a video file by combining an audio clip and an image for android.

  Using cygwin, I was able to create the video by combining an image and an audio clip as follows :

  ffmpeg -i allmapeople.mp3 -i Penguins.jpg video_finale.mpg

  But I want this to happen in the mobile device within my eclipse project.

  Please tell me how this should be done.....