Recherche avancée

Sur d’autres sites (7286)

• Revision 0271ff7775 : Fix speed 7 and speed 12 for rt A recent change has introduced big quality drop

  1er novembre 2014, par Yaowu Xu

  Changed Paths :
   Modify /vp9/encoder/vp9_speed_features.c

  
  
  Fix speed 7 and speed 12 for rt

  A recent change has introduced big quality drops for speed 7 and 12
  for —rt mode. The change reverted the big drop and improved quality
  by 9.5% for speed 7 and 13.4% for speed 12.

  Change-Id : I07b82e3bb6002a73af486a083458c88877bdad01

• Use HLS from Wifi device as input to stream over 4G

  26 février 2017, par pbdev

  I’m building an Android app that streams video from a Wifi device to a Wowza server. It should be quite simple but I can’t figure out how to use both Wifi and 4G at the same time. The device I’m using is a Samsung S5 with Android 6.0.1. To sum it up, this is the goal :

  1. Fetch the video stream from a GoPro device over Wifi.
  2. Send the video stream to a Wowza server over 4G.

  When connected to the GoPro’s Wifi network I can ping the GoPro and see the stream in a MediaPlayer. Since I’m connected to a Wifi device that doesn’t provide internet access, I can’t ping my Wowza server. Once I’ve disabled Wifi this is no problem, by using FFmpeg I can reach the Wowza server over 4G.

  This is the FFmpeg command I want to use to copy the stream to the Wowza server, where 10.5.5.9 is the IP-address of the GoPro :

  ffmpeg -i http://10.5.5.9:8080/live/amba.m3u8 -acodec aac -ar 44100 -ab 48k -vcodec copy -f flv rtmp://username:password@my-wowza-server.com:1935/my-app/my-stream

  If I enable Wifi and connect to the GoPro, 10.5.5.9 is reachable but my-wowza-server.com isn’t. The Samsung S5 provides a Smart network switch which makes the Wowza server reachable but the connection to the GoPro gets lost.

  Is there any way to bind 10.5.5.9 to the Wifi interface of the phone and bind my-wowza-server.com to the cellular interface ?

• ffmpeg does not fill in my provided buffer

  14 avril 2018, par thelearner

  I’m trying to pipe a mp4 video to ffmpeg to generate a thumbnail. Unfortunately, ffmpeg does not fill in my provided buffer, even though the whole command execution is successful.

  I’m reading the video from a http request body :

  videoData, err := ioutil.ReadAll(r.Body)

  This is how I push it to ffmpeg :

  log.Print("Creating thumbnail..")
  
  
  
  width := 640
  
  height := 360
  
  log.Print("Size of the video: ", len(videoData))
  
  
  
  
  
  cmd := exec.Command("ffmpeg", "-i", "pipe:0", "-vframes", "1", "-s", fmt.Sprintf("%dx%d", width, height), "-f",  "singlejpeg", "-frame_size", fmt.Sprintf("%d", totalVideoBytes), "-")
  
  
  
  cmd.Stdin = bytes.NewReader(videoData)
  
  
  
  var imageBuffer bytes.Buffer
  
  cmd.Stdout = &imageBuffer
  
  err := cmd.Run()
  
  
  
  if err != nil {
  
      log.Panic("ERROR")
  
  }
  
  
  
  imageBytes := imageBuffer.Bytes()

  This is the error output :

  [mov,mp4,m4a,3gp,3g2,mj2 @ 0x7ff05d002600]stream 0, offset 0x5ded : partial file

  pipe:0 : Invalid data found when processing input

  Finishing stream 0:0 without any data written to it.

  frame= 0 fps=0.0 q=0.0
  Lsize= 0kB time=-577014:32:22.77 bitrate= -0.0kbits/s speed=N/A
  video:0kB audio:0kB subtitle:0kB other streams:0kB global headers:0kB
  muxing overhead : unknown

  Output file is empty, nothing was encoded (check -ss / -t / -frames parameters if used)

  Thanks a lot, any help is appreciated.