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Somos millones 1
21 juillet 2014, par
Mis à jour : Juin 2015
Langue : français
Type : Video
Autres articles (76)
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Contribute to translation
13 avril 2011You can help us to improve the language used in the software interface to make MediaSPIP more accessible and user-friendly. You can also translate the interface into any language that allows it to spread to new linguistic communities.
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Sur d’autres sites (10462)
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FFMEPG:Why does the video sound become smaller when I use pictures and wavs to compose a video, and there is less audio at the beginning of the video ?
13 novembre 2022, par Naldo hwangffmpeg.exe -r 10 -loop 1 -i 5197.jpg -i audio5197.wav -c:v libx264 -x264-params keyint=1:scenecut=0 -c:a aac -b:a 32k -pix_fmt yuvj420p -shortest out.mp4


I'm trying to make a video with a picture and 7 hours of wav,There is always a few seconds less audio at the beginning of the video, and the sound becomes smaller.


Thanks for reading and help.


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AttributeError : 'FFmpegAudio' object has no attribute '_process' while trying to play audio from URL
13 août 2022, par jmcamacho7I can't find any solution online and I don't know what's wrong.


My code is : (Not pasting the URL getting since that works fine)


from urllib import parse, request
import re
import pafy
from discord import FFmpegPCMAudio, PCMVolumeTransformer

FFMPEG_OPTIONS = {
 'before_options': '-reconnect 1 -reconnect_streamed 1 -reconnect_delay_max 5', 'options': '-vn'
}

@bot.command(pass_context=True)
async def play(ctx, * , search):
 query_string = parse.urlencode({'search_query': search})
 html_content = request.urlopen('http://www.youtube.com/results?' + query_string)
 search_results=re.findall('watch\?v=(.{11})',html_content.read().decode('utf-8'))
 print(search_results[0])
 
 if(ctx.author.voice):
 channel = ctx.message.author.voice.channel
 await ctx.send("https://www.youtube.com/watch?v="+search_results[0]) 
 url = "https://www.youtube.com/watch?v="+search_results[0]
 conn = await channel.connect()
 conn.play(discord.FFmpegAudio(url, **FFMPEG_OPTIONS))
 else:
 await ctx.send("Necesitas estar en un canal de audio para usar este comando")



It just gives me this error everytime I try it :


Traceback (most recent call last):
 File "/home/runner/HakuBot/venv/lib/python3.8/site-packages/discord/player.py", line 103, in __del__
 self.cleanup()
 File "/home/runner/HakuBot/venv/lib/python3.8/site-packages/discord/player.py", line 154, in cleanup
 proc = self._process
AttributeError: 'FFmpegAudio' object has no attribute '_process'



Anyway to solve this ?


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Elegant early exit from a spawned ffmpeg process in C
21 octobre 2016, par jackson80I have a program where I build an ffmpeg command string to capture videos with options input through a gtk3 gui. Once I have all my options selected, I spawn a process with the ffmpeg command string. And I add a child watch to tell me when the process has completed.
// Spawn child process
ret = g_spawn_async (NULL, argin, NULL, G_SPAWN_DO_NOT_REAP_CHILD, NULL, NULL, &pid1, NULL);
if ( !ret )
{
g_error ("SPAWN FAILED");
return;
}
/* Add watch function to catch termination of the process. This function
* will clean any remnants of process */
g_child_watch_add (pid1, (GChildWatchFunc)cb_child_watch, widget );Executing ffmpeg from a terminal using a command line, the program will give an option to input a "q" at the terminal to end the ffmpeg process early.
Is there any way to send a "q" to that spawned process to elegantly end the ffmpeg ? I’m fairly sure I could kill the process using the process id, but I would rather stop it using a mechanism that allows ffmpeg to gracefully exit..
This is running Centos 7, kernel 4.7.5, ffmpeg version 3.0.2.
Since I can still access the terminal where the ffmpeg output is displayed, I’ve tried typing a "q", but it has no effect on the process.