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• FFmpeg command works in terminal but gives an error in php code

  21 mai 2021, par Rider

  Use this command :

  


  ffmpeg -i lecture.mp4 -codec: copy -start_number 0 -hls_time 10 -hls_list_size 0 -f hls filename.m3u8


  


  It works.

  


  $path = '1/';
  $inputFile = 'lecture.mp4';
  $filePath = 'filename.m3u8';
  $commandOutput = exec ('/opt/ffmpeg/ffmpeg -I '.$path .$inputFile. ' -Codec: copy -start_number 0 -hls_time 10 -hls_list_size 0 -f hls'.$path .$filePath);


  


  Using this PHP code I get the error : At least one output file must be specified

  


  What is causing this error ?

  


• Python script doesn't work properly when ran through terminal, but works fine in Jupyter and Visual Studio

  21 octobre 2018, par Ivan Novikov

  I have a script to extract the audio from all video files in a folder.

  The folder with videos is located at : /Users/MyName/Downloads/Video_Audio_files

  When I try to run it through terminal and I’m prompted for the folder path folder = input("Path to folder:"), I drag and drop it there (which is how I got the above path), but the script doesn’t seem to be working (stuck at 0 out of 7 and no output files).

  When I input exactly the same path when prompted in Jupyter Notebook or in Visual Studio it works perfectly !

  Edit : I think I have found the issue, when I drag and drop the folder, there is an extra space (’Downloads/folder ’ instead of ’Downloads/folder’).

  pbar = ProgressBar()
  
  files = []
  
  extensions = []
  
  folder = input("Path to folder:")
  
  #folder = 'Video_Audio_files'
  
  pathlist = Path(folder).glob('**/*.mp4')
  
  for path in pathlist:
  
      path_in_str = str(path)
  
      name = path_in_str.split("/")[1]
  
      files.append(path_in_str.split(".")[0])
  
      extensions.append(path_in_str.split(".")[1])
  
  
  
  os.system('cd ' + folder)
  
  
  
  for i in pbar(range(len(files))):
  
      video_format = extensions[i]
  
      video_name = files[i]
  
      output_format = 'flac'
  
      output_name = video_name + '_audio'
  
  
  
      bashCommand = 'ffmpeg -i ' + video_name + '.'   + video_format + ' -f ' + output_format + ' -ab 192000 -vn ' + output_name + '.' + output_format
  
  #should be of this format: bashCommand = 'ffmpeg -i Video.mp4 -f flac -ab 192000 -vn ExtractedAudio.flac'
  
  
  
      os.system(bashCommand)

• How to limit cpu usage for a terminal command that works on m1 mac and macOS Monterey ?

  18 juin 2024, par mcaay

  I have a m1 macbook pro and I regularly need to do some heave processing with ffmpeg. When I do it, all my 8 cores go at it 100% and my cpu temperature goes to 92°C, which I don't feel comfortable about.

  


  I don't really need 100% speed, I'd much rather see 80°C and wait 5x longer for it to finish.

  


  I use Macs Fan Control which sets my fan at 100% at 75°C, so this helps definitely, but is not enough.

  


  I tried ffmpeg -threads 1 parameter but it doesn't make a difference in compressing speed nor temperature, so I assume it just doesn't work.

  


  I tried cpulimit -l 60 -i ffmpeg ... and it doesn't change a thing, so I assume it also doesn't work. cpulimit -l value gives 100% for every core, so cpulimit -l 800 should be 100%, -l 400 should be 50% and -l 60 should be 7.5%.

  


  I tried nice and it is not for my use case. Even with the lowest priority the task uses all available cpu, resulting in 92°C.

  


  Did anybody figure it out for m1 macs already ?