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Autres articles (35)
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La file d’attente de SPIPmotion
28 novembre 2010, parUne file d’attente stockée dans la base de donnée
Lors de son installation, SPIPmotion crée une nouvelle table dans la base de donnée intitulée spip_spipmotion_attentes.
Cette nouvelle table est constituée des champs suivants : id_spipmotion_attente, l’identifiant numérique unique de la tâche à traiter ; id_document, l’identifiant numérique du document original à encoder ; id_objet l’identifiant unique de l’objet auquel le document encodé devra être attaché automatiquement ; objet, le type d’objet auquel (...) -
Support de tous types de médias
10 avril 2011Contrairement à beaucoup de logiciels et autres plate-formes modernes de partage de documents, MediaSPIP a l’ambition de gérer un maximum de formats de documents différents qu’ils soient de type : images (png, gif, jpg, bmp et autres...) ; audio (MP3, Ogg, Wav et autres...) ; vidéo (Avi, MP4, Ogv, mpg, mov, wmv et autres...) ; contenu textuel, code ou autres (open office, microsoft office (tableur, présentation), web (html, css), LaTeX, Google Earth) (...)
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Supporting all media types
13 avril 2011, parUnlike most software and media-sharing platforms, MediaSPIP aims to manage as many different media types as possible. The following are just a few examples from an ever-expanding list of supported formats : images : png, gif, jpg, bmp and more audio : MP3, Ogg, Wav and more video : AVI, MP4, OGV, mpg, mov, wmv and more text, code and other data : OpenOffice, Microsoft Office (Word, PowerPoint, Excel), web (html, CSS), LaTeX, Google Earth and (...)
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Stream a short video continuously with ffmpeg
12 janvier 2014, par Blue SkyI have a short video (3 sec), and I want to stream it over a UDP address like udp ://127.0.0.1:1000 continously (repeatedly) so that the stream runs forever unless the user stops the streaming session. How can I do so ? Thanks !
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FFMPEG wmv conversion to flv
25 novembre 2012, par Brandon Grossuttianyone using ffmpeg
I have a fairly simple wmv exported by a user from movie maker with standard output and want to convert to .flv using
C :>ffmpeg -i "E :\Jab Core 4 Recounters.wmv" -vcodec flv "C :\Net Projects\SVN\IntegratedAlgorithmics\src\MediaAdmin\MediaAdmin\bin\Debug\Movies\Jab Core 4 Recounters.flv" -ar 44100
the output / error i receive is
FFmpeg version 0.5, Copyright (c) 2000-2009 Fabrice Bellard, et al.
configuration: --enable-gpl --enable-postproc --enable-swscale --enable-avfilt
er --enable-avfilter-lavf --enable-pthreads --enable-avisynth --enable-libfaac -
-enable-libfaad --enable-libmp3lame --enable-libspeex --enable-libtheora --enabl
e-libvorbis --enable-libxvid --enable-libx264 --enable-memalign-hack
libavutil 49.15. 0 / 49.15. 0
libavcodec 52.20. 0 / 52.20. 0
libavformat 52.31. 0 / 52.31. 0
libavdevice 52. 1. 0 / 52. 1. 0
libavfilter 0. 4. 0 / 0. 4. 0
libswscale 0. 7. 1 / 0. 7. 1
libpostproc 51. 2. 0 / 51. 2. 0
built on Mar 16 2009 16:09:18, gcc: 4.2.4 [Sherpya]
[wmv3 @ 0x1c0d490]Extra data: 8 bits left, value: 0
Seems stream 1 codec frame rate differs from container frame rate: 1000.00 (1000
/1) -> 30.00 (30/1)
Input #0, asf, from 'E:\Jab Core 4 Recounters.wmv':
Duration: 00:01:55.99, start: 5.000000, bitrate: 813 kb/s
Stream #0.0: Audio: wmav2, 48000 Hz, stereo, s16, 192 kb/s
Stream #0.1: Video: wmv3, yuv420p, 640x480, 586 kb/s, 30 tbr, 1k tbn, 1k tbc
Output #0, flv, to 'C:\Net Projects\SVN\IntegratedAlgorithmics\src\MediaAdmin\Me
diaAdmin\bin\Debug\Movies\Jab Core 4 Recounters.flv':
Stream #0.0: Video: flv, yuv420p, 640x480, q=2-31, 200 kb/s, 90k tbn, 30 tbc
Stream #0.1: Audio: libmp3lame, 48000 Hz, stereo, s16, 64 kb/s
Stream mapping:
Stream #0.1 -> #0.0
Stream #0.0 -> #0.1
[wmv3 @ 0x1c0d490]Extra data: 8 bits left, value: 0
[libmp3lame @ 0x1c0d8d0]flv does not support that sample rate, choose from (4410
0, 22050, 11025).
Could not write header for output file #0 (incorrect codec parameters ?)i added th -ar switch when i got the error the first time
the codec info i have on the file is as follows
General
Complete name : E:\Jab Core 4 Recounters.wmv
Format : Windows Media
File size : 11.3 MiB
Duration : 2mn 0s
Overall bit rate mode : Variable
Overall bit rate : 780 Kbps
Maximum Overall bit rate : 949 Kbps
Encoded date : UTC 2009-03-07 07:02:41.121
Writing application : 6.0.6000.16386 / Windows Movie Maker
Application : Windows Movie Maker 6.0.6000.16386
Video
ID : 2
Format : VC-1
Format profile : MP@ML
Codec ID : WMV3
Codec ID/Info : Windows Media Video 9
Codec ID/Hint : WMV3
Duration : 2mn 0s
Bit rate mode : Variable
Bit rate : 587 Kbps
Width : 640 pixels
Height : 480 pixels
Display aspect ratio : 4/3
Frame rate : 30.000 fps
Resolution : 24 bits
Scan type : Progressive
Bits/(Pixel*Frame) : 0.064
Stream size : 8.46 MiB (75%)
Language : en-us
Audio
ID : 1
Format : WMA2
Format profile : L3
Codec ID : 161
Codec ID/Info : Windows Media Audio 2
Description of the codec : Windows Media Audio 9.2 - VBR Quality 90, 48 kHz, stereo 1-pass VBR
Duration : 2mn 0s
Bit rate mode : Variable
Bit rate : 186 Kbps
Channel(s) : 2 channels
Sampling rate : 48.0 KHz
Resolution : 16 bits
Stream size : 2.68 MiB (24%)
Language : en-usi see alot of people with this issue with so solution or cause
any ideas would be helpful
thanks in advance -
How can I tell if a file is a valid video stream using RVideo ?
8 février 2012, par fenecI am trying to see if a file has a valid video stream using the RVideo library :
read_file.rb :
require 'rubygems'
require 'rvideo'
file_path="/mnt/glusterfs/video/2012/02/04/2012-02-04 1000 CSPAN United Nations Security Council Meeting (337711).mp4"
puts file_path
file = RVideo::Inspector.new(:file => file_path)I get this error :
rbennacer@services:~$ ruby read_file.rb
/mnt/glusterfs/video/2012/02/04/2012-02-04 1000 CSPAN United Nations Security Council Meeting (337711).mp4
sh: Syntax error: "(" unexpectedEven when I put a backslash before each space character and parenthesis character, I am getting that error.