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Publier une image simplement
13 avril 2011, par ,
Mis à jour : Février 2012
Langue : français
Type : Video
Autres articles (34)
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Keeping control of your media in your hands
13 avril 2011, parThe vocabulary used on this site and around MediaSPIP in general, aims to avoid reference to Web 2.0 and the companies that profit from media-sharing.
While using MediaSPIP, you are invited to avoid using words like "Brand", "Cloud" and "Market".
MediaSPIP is designed to facilitate the sharing of creative media online, while allowing authors to retain complete control of their work.
MediaSPIP aims to be accessible to as many people as possible and development is based on expanding the (...) -
Le plugin : Podcasts.
14 juillet 2010, parLe problème du podcasting est à nouveau un problème révélateur de la normalisation des transports de données sur Internet.
Deux formats intéressants existent : Celui développé par Apple, très axé sur l’utilisation d’iTunes dont la SPEC est ici ; Le format "Media RSS Module" qui est plus "libre" notamment soutenu par Yahoo et le logiciel Miro ;
Types de fichiers supportés dans les flux
Le format d’Apple n’autorise que les formats suivants dans ses flux : .mp3 audio/mpeg .m4a audio/x-m4a .mp4 (...) -
Les tâches Cron régulières de la ferme
1er décembre 2010, parLa gestion de la ferme passe par l’exécution à intervalle régulier de plusieurs tâches répétitives dites Cron.
Le super Cron (gestion_mutu_super_cron)
Cette tâche, planifiée chaque minute, a pour simple effet d’appeler le Cron de l’ensemble des instances de la mutualisation régulièrement. Couplée avec un Cron système sur le site central de la mutualisation, cela permet de simplement générer des visites régulières sur les différents sites et éviter que les tâches des sites peu visités soient trop (...)
Sur d’autres sites (7859)
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How can I use avformat_open_input function (ffmpeg)
5 mai 2016, par johncarrieI have bought a
HD HDMI to UVC
device which has HDMI video source input and UVC for video output here.
I connect it from laptop A (input source HDMI) to laptop B (output USB).
I have installed Ubuntu 14.04 desktop on Laptop B and Win 8.1 on Laptop A.
B also have ffmpeg, opencv and sdl library installed.
My target is to capture video and audio from A viaHD HDMI to UVC
on B.
So I have decided to use libav offfmpeg
.
I saw this and usedavformat_open_input
function but this function returned error.
I thought that the error was occurred because the second parameter ofavformat_open_input
(const char * url
) was invalid.
I know that theurl
should be likevideo:video device name:audio:audio card name
.
How can I indicate the device names ?Here’s the result of
v4l2-ctl --list-devices
command in terminal.HD WebCam (usb-0000:02:03.0-1):
/dev/video0
HD TV CAM (usb-0000:03:00.0-2.1):
/dev/video1And the result of
arecord -l
in terminal.**** List of CAPTURE Hardware Devices ****
card 0: AudioPCI [Ensoniq AudioPCI], device 0: ES1371/1 [ES1371 DAC2/ADC]
Subdevices: 1/1
Subdevice #0: subdevice #0
card 1: CAM [HD TV CAM], device 0: USB Audio [USB Audio]
Subdevices: 1/1
Subdevice #0: subdevice #0Thank you.
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Python/FFMPEG command line issues
1er mars 2019, par 12hysI have a problem with running an FFMPEG command from within a Python script. When I run the following command from the terminal, I can stream video and audio from my attached webcam (Logitech C310) and output to file "out.avi" without any errors.
ffmpeg -f alsa -i default -itsoffset 00:00:00 -f video4linux2 -s 1280x720 -r 25 -i /dev/video0 out.avi
When I run the same command in a Python script below,
def call_command(command):
subprocess.Popen(command.split(' '))
call_command("ffmpeg -f alsa -i default -itsoffset 00:00:00 -f video4linux2 -s 1280x720 -r 25 -i /dev/video0 out.avi")it gives me the error :
Input #0, alsa, from 'default':
Duration: N/A, start: 1317762562.695397, bitrate: N/A
Stream #0.0: Audio: pcm_s16le, 44100 Hz, 1 channels, s16, 705 kb/s
[video4linux2 @ 0x165eb10]Cannot find a proper format for codec_id 0, pix_fmt -1.
/dev/video0: Input/output errorCould anyone shed some light on what could be going on here ? I’ve tried using os.system() as well as subprocess.call() and it gives me the same errors. I’m not sure where to start on what could be going wrong here. I tried searching for the "video4linux2 Cannot find a proper format for codec_id 0, pix_fmt -1" error, but couldn’t find anything consistent.
I’ve also tried putting the "ffmpeg -f..." command in a shell script "test.sh", and giving it executable permissions. I then open terminal, and run "./test.sh", and it works. When I try calling the command "./test.sh" from within my Python script, I’m left with the original error as before. This is the Python command I tried with the test.sh script :
subprocess.call(["./test.sh"])
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Python/FFMPEG command line issues
5 octobre 2011, par 12hysI have a problem with running an FFMPEG command from within a Python script. When I run the following command from the terminal, I can stream video and audio from my attached webcam (Logitech C310) and output to file "out.avi" without any errors.
ffmpeg -f alsa -i default -itsoffset 00:00:00 -f video4linux2 -s 1280x720 -r 25 -i /dev/video0 out.avi
When I run the same command in a Python script below,
def call_command(command):
subprocess.Popen(command.split(' '))
call_command("ffmpeg -f alsa -i default -itsoffset 00:00:00 -f video4linux2 -s 1280x720 -r 25 -i /dev/video0 out.avi")it gives me the error :
Input #0, alsa, from 'default':
Duration: N/A, start: 1317762562.695397, bitrate: N/A
Stream #0.0: Audio: pcm_s16le, 44100 Hz, 1 channels, s16, 705 kb/s
[video4linux2 @ 0x165eb10]Cannot find a proper format for codec_id 0, pix_fmt -1.
/dev/video0: Input/output errorCould anyone shed some light on what could be going on here ? I've tried using os.system() as well as subprocess.call() and it gives me the same errors. I'm not sure where to start on what could be going wrong here. I tried searching for the "video4linux2 Cannot find a proper format for codec_id 0, pix_fmt -1" error, but couldn't find anything consistent.
I've also tried putting the "ffmpeg -f..." command in a shell script "test.sh", and giving it executable permissions. I then open terminal, and run "./test.sh", and it works. When I try calling the command "./test.sh" from within my Python script, I'm left with the original error as before. This is the Python command I tried with the test.sh script :
subprocess.call(["./test.sh"])