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• expected end of line but found unknown token

  17 juin 2017, par Denzil Williams

  Ok so after days of searching, here I am. I am new to ffmpeg, applescript, and terminal.

  I want to use ffmpeg to batch convert a group of selected files in any folder. I was successful in doing this by opening the terminal at the folder location and using this code :

  for f in *.flv; do ffmpeg -i "$f" -acodec libmp3lame -b:a 256k "${f%.flv}.mp3" && rm "$f"; done

  which finds all flv files, and converts it to 256 bit rate mp3, then deletes the original files.

  Now I want it to be more automated, so I looked into creating a service. I tried running an apple script through automator, which I want it to open the terminal at the folder location the file then run the code to convert the files. Here’s the code I attempted :

  tell application "Finder" to set currentFolder to target of front Finder window as text
  
  set theWin to currentFolder's POSIX path
  
  
  
  tell application "Terminal"
  
      if not (exists window 1) then reopen
  
      activate
  
      do script "cd " & quoted form of theWin & ";clear" in window 1
  
      tell application "Terminal"
  
          do script "for f in *.flv; do ffmpeg -i "$f" -acodec libmp3lame -b:a 256k "${f%.flv}.mp3" && rm "$f"; done"
  
      end tell
  
  end tell

  The first part of code opens up terminal at the folder location just fine. But when I add the part with the ffmpeg code it crashes. The error is apparently with the "$", those are what light up as the error, the error message says "Expected end of line, but found unknown token". Looking for some assistance please. I need the "$" because those are what make the loop work for renaming the files and such.

• How to Convert video into mp3 format using ffmpeg in nodejs and angular and then save converted audio into the database

  2 septembre 2021, par Amir Shahzad

  This is nodejs server side file

  


  const express = require('express');
const ffmpeg  = require('fluent-ffmpeg');
const fileUpload = require('express-fileupload');
const mongoose = require('mongoose');
const cors   = require('cors')
const app = express();
const Video = require('./models/video');
mongoose.connect('mongodb://localhost:27017/YoutubeApp', {
    useNewUrlParser: true,
    useUnifiedTopology: true,
});
const db = mongoose.connection;
db.on('error', console.error.bind(console, 'connection error'));
db.once('open', () => {
   console.log('Data Base Connected Successfully!');
});

app.use(fileUpload({
   useTempFiles: true,
   tempFileDir: 'temp/'
}));
app.use(express.json());
app.use(express.urlencoded({ extended: true }));
app.use(cors({ origin: 'http://localhost:4200' }));


ffmpeg.setFfmpegPath('/usr/bin/ffmpeg');

app.post('/mp4tomp3', (req, res) => {
  convertdata = req.body;
  console.log('path of innput is', req.body);
  function convert(input, output, callback) {
     ffmpeg(input)
         .output(output)
         .on('end', function() {                    
             console.log('conversion ended');
             callback(null);
           }).on('error', function(err){
              console.log('error: ', err.code, err.msg);
              callback(err);
           }).run();
      }
     convert(convertdata, './temp/output.mp3', function(err){
        if(!err) {
          console.log('conversion complete');

 
     }
 })

 app.listen(3000, () => {
    console.log('Server Start On Port 3000')
 })


  


  In Convert function i not know how i can get input by the user i'm new in angular Please anyone can solve this out thanks in advance

  


  This is video model file

  


  const mongoose = require("mongoose");
const Schema = mongoose.Schema;

const videoSchema = new Schema({
    mp4: String,
});
module.exports = mongoose.model("Videos", videoSchema);


  


  **This is Typescript code in angular client side that handle user input and select video **

  


  import { ThrowStmt } from '@angular/compiler';
import { Component, OnInit } from '@angular/core';
import { FormBuilder, FormGroup, Validators } from '@angular/forms';
import { VideoConversionService } from 'src/services/video-conversion.service';

@Component({
  selector: 'app-root',
  templateUrl: './app.component.html',
  styleUrls: ['./app.component.css']
})
export class AppComponent implements OnInit {

   submitted =false;
   form! : FormGroup
   data:any

   constructor(private formBuilder: FormBuilder,
       private videoService: VideoConversionService){}

   creatForm(){
    this.form = this.formBuilder.group({
    mp4: ['', Validators.required],
  });
  }
   ngOnInit(): void {
   this.creatForm();

  }


  convertVideo(){
    this.submitted = true
    this.videoService.conversion(this.form.value).subscribe(res => {
    this.data = res;
 })
 }

 }


  


  I do not know how to create logic to do that (convert video into audio using angular framework)

  


  This is app.component.html file where i want to get video from the user using input field

  


  <div class="container">&#xA;   <h1>Video Proccessing App</h1>&#xA;   <form>&#xA;     <input type="file" formcontrolname="mp4" />&#xA;     <input type="submit" value="Convert" />&#xA;  </form>&#xA;</div>&#xA;

  


  


  But my code is not working and video is not converting into audio

  


  This is my video service file where i calling nodejs api to perform the task

  


  import { Injectable } from '@angular/core';
import { HttpClient  } from '@angular/common/http';
@Injectable({
   providedIn: 'root'
})
export class VideoConversionService {

constructor(private httpClient: HttpClient) { }

conversion(data: any){
   return this.httpClient.post('http://localhost:3000/mp4tomp3', data)
}
}


  


  Please anyone can solve my problem Thanks in advance

  


• ffmpeg jpeg stream to webm only creates a file .webm with 1 frame (snapshot) or empty .webm file (mjpeg)

  14 novembre 2016, par moeiscool

  my problem is that when i try to turn a series of jpegs into a webm video. I either get a webm file with a single frame or a webm file with nothing in it (0 kb).

  var fs = require('fs');
  
  var path = require('path');
  
  
  
  var outStream = fs.createWriteStream(__dirname+'/output.webm');
  
  var ffmpeg = require('fluent-ffmpeg');

  this one is a mjpeg stream URL. it produces a file with nothing.

  //var proc = new ffmpeg({source:'http://xxx.xxx.xxx.xxx/goform/stream?cmd=get&channel=0',timeout:0})

  this one is a snapshot URL. it produces a file with a single frame.

  var proc = new ffmpeg({source:'http://xxx.xxx.xxx.xxx/snapshot/view0.jpg',timeout:0})
  
  
  
  .fromFormat('mjpeg')
  
  .size('2048x1536')
  
  .toFormat('webm')
  
  .withVideoBitrate('800k')
  
  .withFps(20)

  I have tried to use pipe instead but no dice :(

  //.pipe(outStream,{end:false});
  
  .writeToStream(outStream,{end:false})

  any help is appreciated.

  at this point i am up for using a basic shell command with exec but when i try that i just get errors also. Yes, it goes without saying I am a noob.

  Side note :

  I have tried things like zoneminder but it just breaks with our cameras and the number of cameras. so i am making a bare bones solution to record them. With our current cloud service we are missing very important moments and its costing more in energy and time.