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  • MediaSPIP 0.1 Beta version

    25 avril 2011, par

    MediaSPIP 0.1 beta is the first version of MediaSPIP proclaimed as "usable".
    The zip file provided here only contains the sources of MediaSPIP in its standalone version.
    To get a working installation, you must manually install all-software dependencies on the server.
    If you want to use this archive for an installation in "farm mode", you will also need to proceed to other manual (...)

  • Multilang : améliorer l’interface pour les blocs multilingues

    18 février 2011, par

    Multilang est un plugin supplémentaire qui n’est pas activé par défaut lors de l’initialisation de MediaSPIP.
    Après son activation, une préconfiguration est mise en place automatiquement par MediaSPIP init permettant à la nouvelle fonctionnalité d’être automatiquement opérationnelle. Il n’est donc pas obligatoire de passer par une étape de configuration pour cela.

  • Les tâches Cron régulières de la ferme

    1er décembre 2010, par

    La gestion de la ferme passe par l’exécution à intervalle régulier de plusieurs tâches répétitives dites Cron.
    Le super Cron (gestion_mutu_super_cron)
    Cette tâche, planifiée chaque minute, a pour simple effet d’appeler le Cron de l’ensemble des instances de la mutualisation régulièrement. Couplée avec un Cron système sur le site central de la mutualisation, cela permet de simplement générer des visites régulières sur les différents sites et éviter que les tâches des sites peu visités soient trop (...)

Sur d’autres sites (11644)

  • Revision ad479a9b3d : multi-res : modify memory allocation code Reverted part of change in memory alll

    23 mai 2012, par Yunqing Wang

    Changed Paths : Modify /vp8/vp8_cx_iface.c multi-res : modify memory allocation code Reverted part of change in memory alllocation code, which ensures that the function returns 0 and encoder works correctly when CONFIG_MULTI_RES_ENCODING isn't turned on. Change-Id : (...)

  • How to run a command in python with file paths containing spaces ?

    24 juillet 2023, par tomatochan

    I'm developing a program in Python that requires the use of FFMPEG. In one step, I need to create a video from a text file containing the list of images (path and duration) that need to be assembled to make a video. To do this, I use the following code :

    


    cmd = [ffmpeg, "-y", "-f", "concat", "-safe", "0", "-i", tmp, "-c:v", "libx264", "-r", "25", "-pix_fmt", "yuv420p", out]
subprocess.run(cmd)
# os.system(" ".join(cmd)) # returns same error


    


    What returns the error : The syntax of the file, directory or volume name is incorrect.

    


    I know that paths can be problematic when they contain spaces, and as my username has one, I've taken care to quote the paths in such a way that :

    


    ffmpeg = '"C:\Users\John Doe\Documents\ffmpeg\bin\ffmpeg.exe"'
tmp = '"C:\Users\John Doe\Desktop\path\to\file.txt"'
out = '"C:\Users\John Doe\Desktop\path\to\video.mp4"'


    


    When I print(" ".join(cmd)), this is what I get in my terminal :

    


    "C:\Users\John Doe\Documentsffmpeg\binffmpeg.exe" -y -f concat -safe 0 -i "C:\Users\John Doe\Desktop\path\to\file.txt" -c:v libx264 -r 25 -pix_fmt yuv420p "C:\Users\John Doe\Desktop\path\to\video.mp4"


    


    However, the problem persists.
Has anyone ever had this problem and managed to solve it ?

    


    I've also tried the method where you have to escape the spaces (taking care to replace the \ with / and then the with \ ) but nothing works... The error persists.

    


    For your information, here are the contents of one of my .txt files

    


    file C:\Users\John Doe\Desktop\path\to\image_1.png
duration 0.04
file C:\Users\John Doe\Desktop\path\to\image_2.png
duration 0.04
file C:\Users\John Doe\Desktop\path\toimage_3.png
duration 0.04


    


    When I quote the paths in the .txt files

    


      

    • subprocess gives me the error :
PermissionError: [WinError 5] Access denied
    • 


    • os.system gives me the error :
    • 


    


    C:\Users\John' is not recognized as an internal or external command, an executable program or a command file.
The syntax of the file, directory or volume name is incorrect.


    


  • Requesting header information of a file

    11 janvier 2012, par 0v3rrid3

    is there anyway I can request only the header information of any media. For example I just want to request header information of any video file so as to find its video length. I tried using ffmpeg -i {video_url} and did the work but I noticed that it actually downloads the given media in local storage and returns back the header information which obviously increases roundtrip time.

    So I would really appreciate if there is any idea for finding the length of media in a fly. BTW I have a ruby on rails application where I need to implement this.