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  • ffmpeg not creating a name for image after thumbnail generation C#

    15 août 2012, par Lynx

    I just learn how to use ASP.NET and learn C# last month and now I am having a problem.
    I am experimenting on how to generate thumbnail using ffmpeg in C#. The thumbnail successfully generated in intended folder but there is no name for the image file.
    what I want to do is to create thumbnail and automatically named the jpg file same as the video file.

    I can't figure out what is wrong with my code ; in fact, I don't even understand the code completely as I copied the code from internet and change the folder path of the files.

    private void generateThumbnails(string filename)
    {
       string[] setThum = filename.Split('.');
       string thumb_path = setThum[0] + ".jpg";
       filename = "C:\\ramky\\al.avi";
       string thumbpath, thumbname;//, videopath;
       string thumbargs, inputfile;
       thumbpath = "C:\\ramky\\";
       thumbname = thumbpath + thumb_path;
       inputfile = filename;
       thumbargs = "-i \"" + inputfile + "\" -s 240*150 -ss 1 -vframes 1 -f image2 \"" + thumbname + "\"";

       Process thumbproc = new Process();
       thumbproc = new Process();

       thumbproc.StartInfo.FileName = "C:\\ffmpeg\\ffmpeg.exe";
       thumbproc.StartInfo.Arguments = thumbargs;
       thumbproc.StartInfo.UseShellExecute = false;
       thumbproc.StartInfo.CreateNoWindow = true;
       thumbproc.StartInfo.RedirectStandardOutput = false;

       try
       {
           thumbproc.Start();
           if (thumbproc != null)
           {
               thumbproc.Close();
           }
       }
    }

    Your help will be really appreciated.

  • ffmpeg not creating a name for image after thumbnail generation

    15 août 2012, par Lynx

    I just learn how to use ASP.NET and learn C# last month and now I am having a problem.
    I am experimenting on how to generate thumbnail using ffmpeg in C#. The thumbnail successfully generated in intended folder but there is no name for the image file.
    what I want to do is to create thumbnail and automatically named the jpg file same as the video file.

    I can't figure out what is wrong with my code ; in fact, I don't understand the code completely as I copied the code from internet and only change the folder path of the files.

    private void generateThumbnails(string filename)
    {
       string[] setThum = filename.Split('.');
       string thumb_path = setThum[0] + ".jpg";
       filename = "C:\\ramky\\al.avi";
       string thumbpath, thumbname;//, videopath;
       string thumbargs, inputfile;
       thumbpath = "C:\\ramky\\";
       thumbname = thumbpath + thumb_path;
       inputfile = filename;
       thumbargs = "-i \"" + inputfile + "\" -s 240*150 -ss 1 -vframes 1 -f image2 \"" + thumbname + "\"";

       Process thumbproc = new Process();
       thumbproc = new Process();

       thumbproc.StartInfo.FileName = "C:\\ffmpeg\\ffmpeg.exe";
       thumbproc.StartInfo.Arguments = thumbargs;
       thumbproc.StartInfo.UseShellExecute = false;
       thumbproc.StartInfo.CreateNoWindow = true;
       thumbproc.StartInfo.RedirectStandardOutput = false;

       try
       {
           thumbproc.Start();
           if (thumbproc != null)
           {
               thumbproc.Close();
           }
       }
    }
  • Faster Thumbnail/Image Extraction from Video using FFMPEG ?

    27 août 2012, par mirroredAbstraction

    I am using this command to extract a series of images from a video to express them as a visual time-frame of the video.

    ffmpeg -i inputfile.mp4  -r  1  -t  12  image-%d.jpeg

    Most of my videos are in mp4 format. I am able to extract the images successfully but the time taken for extraction is too long.

    Is there any way I could reduce the time for image extraction ?

    EDIT : It is taking me 60 secs to get 8 thumbnails from a 15 sec long video encoded in MP4 format, I am doing this operation on my Galaxy Nexus(Android Phone) is there any way to improve the speed of operation, ideally I want it be less than  10secs.