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• PHP's exec() not executing command for FFmpeg

  16 septembre 2011, par tundoopani

  I have installed ffmpeg on my server and it works fine via my terminal. I'm able to successfully convert a file to webm format, so I'm sure the installation is fine. I'm also sure that I only have one installation of ffmpeg installed on my machine.

  A problem arises when I try to convert files through PHP via PHP's exec(). When I run the same commands, I ran in the terminal, nothing happens. I looked around stackoverflow and other parts of the net for some help. I tried this to see the output :

  exec($cmd, $out, $rv);
  
  echo "output is:\n".implode("\n", $out)."\n exit code:$rv\n";

  The output is : "output is : exit code:127"

  The command I'm using is in this format :

  ffmpeg -i "sample.mov" -vcodec libvpx  -r 30 -b "644k" -acodec libvorbis -ab 128000   -ar "44100" -ac 2 -s "352x198" "sample.webm"

  I've tried replacing "ffmpeg" with the full path to FFmpeg but that did not work.

  Why isn't the script running the command correctly and converting the files ?

  Thank you !

• FFmpeg - PHP Error Code 127

  25 avril 2013, par Kit

  I am trying to execute FFmpeg from php. I have installed FFmpeg-php, and the extension is in the modules directory and it shows up in phpinfo. FFmpeg is working fine as I can run the command in a terminal and it outputs the video. However, when I try and run the command from php using the following script :

  exec(ffmpeg -i input.avi output.avi);

  But I get a '127' error code.

  The extension is loaded in using :

  $extension      = "ffmpeg";
  
  $extension_soname   = $extension . "." . PHP_SHLIB_SUFFIX;
  
  $extension_fullname = PHP_EXTENSION_DIR . "/" . $extension_soname;
  
  
  
  // Locate Extension
  
  define('FFMPEG_LIBRARY', '/usr/local/bin/ffmpeg');
  
  
  
  // Load Extension
  
  if (!extension_loaded($extension))
  
      echo dl($extension_soname) or die("Can't load extension $extension_fullname\n");

  I have also tried defining the aboslute extension location in the command :

  exec(/usr/local/bin/ffmpeg-i input.avi output.avi);

  Again, this works in the terminal but still returns the same erro code using the php exec().

  Has anyone got any ideas ?

  Thank you.

• FFMpeg giving invalid argument error with python subprocess

  23 janvier 2020, par Emre Erol

  I am trying to convert a file or microphone stream to 22050 sample rate and change tempo to double. I can do it using terminal with below code ;

  #ffmpeg -i test.mp3 -af asetrate=44100*0.5,aresample=44100,atempo=2 output.mp3 

  But i can not run this terminal code with python subprocess. I try many things but every time fail. Generaly i am taking Requested output format ’asetrate’ or ’aresample’ or ’atempo’ is not suitable output format errors. Invalid argument. How can i run it and take a stream with pipe ?

  song = subprocess.Popen(["ffmpeg.exe", "-i", sys.argv[1], "-f", "asetrate", "22050", "wav", "pipe:1"],
  
                          stdout=subprocess.PIPE)