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Autres articles (49)
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Le plugin : Podcasts.
14 juillet 2010, parLe problème du podcasting est à nouveau un problème révélateur de la normalisation des transports de données sur Internet.
Deux formats intéressants existent : Celui développé par Apple, très axé sur l’utilisation d’iTunes dont la SPEC est ici ; Le format "Media RSS Module" qui est plus "libre" notamment soutenu par Yahoo et le logiciel Miro ;
Types de fichiers supportés dans les flux
Le format d’Apple n’autorise que les formats suivants dans ses flux : .mp3 audio/mpeg .m4a audio/x-m4a .mp4 (...) -
MediaSPIP v0.2
21 juin 2013, parMediaSPIP 0.2 is the first MediaSPIP stable release.
Its official release date is June 21, 2013 and is announced here.
The zip file provided here only contains the sources of MediaSPIP in its standalone version.
To get a working installation, you must manually install all-software dependencies on the server.
If you want to use this archive for an installation in "farm mode", you will also need to proceed to other manual (...) -
Des sites réalisés avec MediaSPIP
2 mai 2011, parCette page présente quelques-uns des sites fonctionnant sous MediaSPIP.
Vous pouvez bien entendu ajouter le votre grâce au formulaire en bas de page.
Sur d’autres sites (8209)
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Receiving UDP streams on my web server
25 novembre 2013, par user3032143I have a Winform C# Desktop application.
This is my overall aim :
I have a constant stream of images from which I acquire using a VLC wrapper receiving a RTSP stream from my IP camera.
I am doing image processing on these separate jpegs and at the same time I am wanting to upload these jpegs to my web server so my User can view these streaming jpegs live a video.
Now, I have accomplished this so far by uploading each jpeg to my server using a [Web method]. But, I am trying to push my knowledge to make it more efficient.
Now, i know if I use a video encoder - like OGG (used because it is Open Source) I can use ffmpeg called from my client code using the Process class so to convert images to that video format.
Doing this saves a lot of memory when comparing that 1 ogg file to the separate bytes added up in total from all the individual jpegs.
These are the arguments I pass to ffmpeg to achieve that :
-f image2 -r 10 -i {location of jpegs}+"\img%05d.jpg -crf 23 -y -r 10 -f outputfile.ogg
Now, I could take this a step further and not output to a physical file but instead to the base stream of the Process class. I would use these arguments to accomplish that :
-f image2 -r 10 -i {location of jpegs}+"\img%05d.jpg -crf 23 -y -r 10 -f ogg -
and in my code I would get the memory stream like so :
mStandardOutput = serverBuild.StandardOutput.BaseStream;
mStandardOutput.BeginRead(mReadBuffer, 0, mReadBuffer.Length, StandardOutputReadCallback, null);
serverBuild.WaitForExit();
data = mStandardOutputMs.ToArray();
mStandardOutput.Close();Now ultimately, I would like to replace :
-i {location of jpegs}+"\img%05d.jpg
with a constant flow of jpegs in a memory stream like so :
ffmpeg -f mjpeg -i - -r 10 -c:v libtheora -q:v 7 -f ogg -
.. by over-writing the stdin...
But I have not done this yet because I want to 1st try getting the ogg to be received within my web server.
From there I would extract the jpegs to be accessible somehow via my web application written in asp.net 4.0.
But first thing is first I want to just see if I can receive the UDP stream from my client.
So, I create a test C# application to open and listen write from the client stream..
this is my code :Socket socket = new Socket(AddressFamily.InterNetwork, SocketType.Dgram, ProtocolType.Udp);
public Form1()
{
InitializeComponent();
socket.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.ReuseAddress, true);
string ip = "My Server IP Address";
int port = 3000;
socket.Bind(new IPEndPoint(IPAddress.Parse(ip), port));
}
private void button1_Click(object sender, EventArgs e)
{
try
{
var buffer = new byte[1024];
while (true)
{
Application.DoEvents();
int numBytesReceived = socket.Receive(buffer);
if (numBytesReceived > 0)
{
File.WriteAllBytes("c:\\udp\\test.ogg", buffer);
}
}
}
catch (Exception _ex)
{
MessageBox.Show(_ex.ToString());
}
}But, I get this error :
A message sent on a datagram socket was larger than the internal message buffer or some other network limit, or the buffer used to receive a datagram into was smaller than the datagram itself.
What am I doing wrong please ?
Thanks
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avcodec/vp9dsp : add DC only versions for idct/idct.
22 novembre 2013, par Clément Bœschavcodec/vp9dsp : add DC only versions for idct/idct.
before :
./ffmpeg -v 0 -nostats -i /samples/vp9/etv.webm -f null - 16.29s user 0.02s system 99% cpu 16.323 total
./ffmpeg -v 0 -nostats -i /samples/vp9/etv.webm -f null - 16.32s user 0.01s system 99% cpu 16.351 total
./ffmpeg -v 0 -nostats -i /samples/vp9/etv.webm -f null - 16.27s user 0.05s system 99% cpu 16.335 totalafter :
./ffmpeg -v 0 -nostats -i /samples/vp9/etv.webm -f null - 15.22s user 0.03s system 99% cpu 15.257 total
./ffmpeg -v 0 -nostats -i /samples/vp9/etv.webm -f null - 15.20s user 0.02s system 99% cpu 15.237 total
./ffmpeg -v 0 -nostats -i /samples/vp9/etv.webm -f null - 15.19s user 0.02s system 99% cpu 15.227 total -
FFmpeg : How to estimate number of samples in audio stream ?
15 août 2017, par MariusI’m currently writing a small application that’s making use of the FFmpeg library in order to decode audio files (especially avformat and swresample) in C++.
Now I need the total number of samples in an audio stream. I know that the exact number can only be found out by actually decoding all the frames, I just need an estimation. What is the preferred method here ? How can I find out the duration of a file ?