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Autres articles (105)

  • Encoding and processing into web-friendly formats

    13 avril 2011, par

    MediaSPIP automatically converts uploaded files to internet-compatible formats.
    Video files are encoded in MP4, Ogv and WebM (supported by HTML5) and MP4 (supported by Flash).
    Audio files are encoded in MP3 and Ogg (supported by HTML5) and MP3 (supported by Flash).
    Where possible, text is analyzed in order to retrieve the data needed for search engine detection, and then exported as a series of image files.
    All uploaded files are stored online in their original format, so you can (...)

  • Formulaire personnalisable

    21 juin 2013, par

    Cette page présente les champs disponibles dans le formulaire de publication d’un média et il indique les différents champs qu’on peut ajouter. Formulaire de création d’un Media
    Dans le cas d’un document de type média, les champs proposés par défaut sont : Texte Activer/Désactiver le forum ( on peut désactiver l’invite au commentaire pour chaque article ) Licence Ajout/suppression d’auteurs Tags
    On peut modifier ce formulaire dans la partie :
    Administration > Configuration des masques de formulaire. (...)

  • Qu’est ce qu’un masque de formulaire

    13 juin 2013, par

    Un masque de formulaire consiste en la personnalisation du formulaire de mise en ligne des médias, rubriques, actualités, éditoriaux et liens vers des sites.
    Chaque formulaire de publication d’objet peut donc être personnalisé.
    Pour accéder à la personnalisation des champs de formulaires, il est nécessaire d’aller dans l’administration de votre MediaSPIP puis de sélectionner "Configuration des masques de formulaires".
    Sélectionnez ensuite le formulaire à modifier en cliquant sur sont type d’objet. (...)

Sur d’autres sites (10712)

  • Thumbnail is not generated while uploading a video which is downloaded from the same server

    16 avril 2014, par nit3ch

    I am using drupal 7 video module and ffmpeg together to upload video on my site.
    My problem :

    1. Upload a video, everything works fine, thumbnail is generated and video is uploaded successfully
    2. Now download the above uploaded video.
    3. Now Try to upload the same video, on same drupal site.

    Thumbnail is not generating and also I am not able to play the newly uploaded video.
    In all other cases video upload is working fine, I am able to upload same video again and again with no fuss,but when I try to upload the downloaded video , everything goes wrong even if I change the file name after downloading the video and uploading again.

    Please let me know if I am not clear, will try to explain more.

  • Python ThreadedTCPServer : "Name or service not known"

    11 avril 2014, par Hal

    I was developing a ThreadedTCPServer to communicate with a PHP application also residing in this same machine. This is suppose to receive requests from this PHP app and to convert some videos locally using ffmpeg.

    Here's the code :

    # -*- coding: utf-8 -*-
    import os
    import socket
    import threading
    import logging.config
    import SocketServer, time
    from queuev2 import QueueServer

    logging.basicConfig(format='[%(asctime)s.%(msecs).03d] %(message)s', datefmt='%Y-%m-%d %H:%M:%S', filename=os.path.join(os.path.dirname(os.path.realpath(__file__)), 'converter.log'), level=logging.INFO)

    class ThreadedTCPRequestHandler(SocketServer.BaseRequestHandler):

       def handle(self):
           data = self.request.recv(1024)
           cur_thread = threading.current_thread()
           response = "{}: {}".format(cur_thread.name, data)
           videoPool.add(data)
           print "Output! %s" % data
           self.request.sendall(response)

    class ThreadedTCPServer(SocketServer.ThreadingMixIn, SocketServer.TCPServer):
       pass

    if __name__ == "__main__":

       logging.info("Initializing...")
       videoPool = QueueServer()
       HOST, PORT = "localhost", 6666

       server = ThreadedTCPServer((HOST, PORT), ThreadedTCPRequestHandler)
       ip, port = server.server_address

       # Start a thread with the server -- that thread will then start one
       # more thread for each request
       server_thread = threading.Thread(target=server.serve_forever)

       # Exit the server thread when the main thread terminates
       server_thread.daemon = True
       server_thread.start()

       print("Server loop running in thread: %s" % server_thread.name)

       # "Groundhog day" time
       while True:
           time.sleep(999)
           pass

       #server.shutdown()

    This works well in my development laptop, but on the server i'm getting the following error :

    Traceback (most recent call last):
     File "server.py", line 31, in <module>
       server = ThreadedTCPServer((HOST, PORT), ThreadedTCPRequestHandler)
     File "/usr/lib/python2.7/SocketServer.py", line 408, in __init__
       self.server_bind()
     File "/usr/lib/python2.7/SocketServer.py", line 419, in server_bind
       self.socket.bind(self.server_address)
     File "/usr/lib/python2.7/socket.py", line 224, in meth
       return getattr(self._sock,name)(*args)
    socket.gaierror: [Errno -2] Name or service not known
    </module>

    I'm guessing it has to do with the port I'm using (6666), but I've tried others and it hasn't been working. Would Unix Domain Sockets be of use here ? Can you give me an example ?

  • How to http stream video from a frequently updated image

    27 avril 2017, par alez

    How can I obtain an HTTP video stream from a single image file that is frequently updated (every 50ms) ?

    The file is on a Windows 7 machine, I can use C# but I can also send a potential stream to a linux machine.

    I would try whith vlc and the fake module, but it seems not more supported. I’ve tried also with a pipe from ffmpeg (also over an udp localhost stream) but it doesn’t work.