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• Anomalie #2308 (Nouveau) : raccourcis clavier pour les formulaires de texte

  9 septembre 2011, par Fil Up

  dans les textarea, ctrl-i et ctrl-b devraient faire et (indépendamment de la présence ou pas de la barre typo) tout comme ctrl-s enregistre

• How to access uploaded file from multer ?

  13 avril 2017, par Somename

  Im able to upload an image to S3. Now, if the file selected is .gif, I want to be able to convert the .gif file to .mp4 and upload the converted file to S3. I am able to convert a .gif to .mp4 with ffmpeg only if I give the path of the file. How do I access the uploaded file from Multer ? Below is my code :

  var express = require('express');
  
  var bodyParser = require('body-parser');
  
  var app = express();
  
  var aws = require('aws-sdk');
  
  var multer = require('multer');
  
  var multerS3 = require('multer-s3');
  
  var s3 = new aws.S3();
  
  var ffmpeg = require('fluent-ffmpeg');
  
  
  
  
  
  var upload = multer({
  
      storage: multerS3({
  
          s3: s3,
  
          bucket: 'myBucket',
  
          key: function (req, file, cb) {
  
              console.log(file);
  
              var extension = file.originalname.substring(file.originalname.lastIndexOf('.')+1).toLowerCase();
  
  
  
                  if(extension=="gif"){
  
                  console.log("Uploaded a .gif file");
  
  
  
                  ffmpeg(file) //THIS IS NOT WORKING
  
                      .setFfmpegPath("C:\\ffmpeg\\bin\\ffmpeg.exe")
  
                        .output('./outputs/2.mp4')    //TRYING TO UPLOAD LOCALLY, WHICH FAILS
  
                        .on('end', function() {
  
                          console.log('Finished processing');
  
                        })
  
                        .run();
  
              }
  
  
  
              cb(null, filename);
  
          }
  
      })
  
  });

  I’m trying to access the uploaded file like this : ffmpeg(file) since file is an argument passed in the multer function.

  My form :

  <form action="/upload" method="post" enctype="multipart/form-data">
  
      <input type="file" /> <br />
  
      <input type="submit" value="Upload" />
  
  </form>

  In which part of the process do I convert the file ?

  Please help. Many thanks.

• Getting FFProbe Information With Python

  4 juin 2024, par jesse

  I've been attempting to figure this out for forever now (I'm new to programming) and I can't figure it out.

  



  I'm attempting to build a script that will test the file, and give me output from which I can get information like "Audio Format" that I can then put into the filename. However, I can't even get the script to return any file info. I've hit a wall at inserting an input file...

  



  So at this point I just need help getting it to spit out info based on the argvs I've thrown in. Hopefully I'll be able to figure out how to parse the audio info from that.

  



  My attempt that seems to be close :

  



  #!/usr/bin/python
import os, sys, subprocess, shlex, re
from subprocess import call
def probe_file(filename):
    p = subprocess.Popen(['/opt/local/bin/ffprobe', '-show_format', '-pretty', '-loglevel quiet', -i filename], stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE, shell=True)
    print filename
    print p.communicate()
[probe_file (f) for f in os.listdir('.') if not f.startswith('.')]