Recherche avancée

Sur d’autres sites (7046)

• Running ffmpeg in Docker environment on AWS EC2 [duplicate]

  5 mai 2024, par must

  I want to use FFMPEG inside my Java application.
I want to instal ffmpeg in environment where this app is running.

  


  My current Dockerfile :

  


  # Stage 1: Build the application
FROM maven:3.8.4-openjdk-17 AS build
WORKDIR /app
COPY pom.xml .
COPY src ./src
RUN mvn clean install -Dmaven.test.skip=true

# Stage 2: Run the application
FROM openjdk:17
WORKDIR /app
COPY --from=build /app/target/application.jar ./app.jar
EXPOSE 8080
CMD ["java", "-jar", "-Dspring.profiles.active=pr", "app.jar"]


  


  I simply built a docker image by running docker buildx build --platform linux/amd64 -t repo/app:1.0 .

  


  Then in AWS Console I run docker run and pull built image.

  


  Everyone writes about adding

  


  RUN apt-get -y update && apt-get -y upgrade && apt-get install -y --no-install-recommends ffmpeg


  


  but I cannot do it as I'm building image on MacOS and I do no have apt-get command.

  


  When I was trying to pull some image form DockerHub FFMPEG could not be found.

  


  I tried this one : https://hub.docker.com/r/jrottenberg/ffmpeg

  


  and declared DockerFile as :

  


  # Stage 1: Build the application
FROM maven:3.8.4-openjdk-17 AS build
WORKDIR /app
COPY pom.xml .
COPY src ./src
RUN mvn clean install -Dmaven.test.skip=true

# Stage 2: Install ffmpeg
FROM jrottenberg/ffmpeg:latest AS ffmpeg

# Stage 3: Run the application
FROM openjdk:17
WORKDIR /app
COPY --from=build /app/target/application.jar ./app.jar
COPY --from=ffmpeg /usr/local/bin/ffmpeg /usr/local/bin/ffmpeg

EXPOSE 8080
CMD ["java", "-jar", "-Dspring.profiles.active=pr", "app.jar"]


  


  but still it did not work. I get :

  


  ffmpeg: error while loading shared libraries: libavdevice.so.58: cannot open shared object file: No such file or directory


  


  I'm using Amazon Linux on EC2.

  


  Can someone get me on the right track ?

  


• How to retrieve mediainfo from raw data in Flask app ?

  28 novembre 2023, par Hi-tecX

  I'm uploading an audio file via Flask's FileField form and I want to get to its mediainfo. Uploaded audio is available in the form of bytrs.

  


  To obtain a path for pydub.utils.mediainfo function, I was trying :

  


  @app.route('/upload', methods=['GET', 'POST'])
def upload():
    audiofile = form.file.data.read()
    # type(audiofile) == bytes

    with tempfile.NamedTemporaryFile(mode='w+b', suffix='.mp3') as tmp:
        tmp.write(audiofile)
        # tmp.name == C:\Users\JUSTME~1\AppData\Local\Temp\tmp0wky2_wq.mp3
        print(pydub.utils.mediainfo(tmp.name))


  


  But pydub.utils.mediainfo returns an empty dict object.
Is it possible to solve the problem ?

  


  Inspired by this quastion.

  


• Anomalie #3906 : Déplacer l’explication avant le champ

  27 février 2017, par - Equipement

  Bonjour,

  Pour mémoire, le critère 11.14 du RGAA mentionne plusieurs solutions :
  - Il existe des indications avant les champs de formulaire
  - Il existe des indications dans l’étiquette (balise label, attribut title, propriété aria-label, passage de texte lié via la propriété aria-labelledby) du champ de formulaire
  - Il existe des indications dans un passage de texte lié par la propriété ARIA aria-describedby

  Cordialement
  Equipement