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• doc/filters/crop: drop unmatched quote in example

  11 May 2023, by Andriy Utkin

  doc/filters/crop: drop unmatched quote in example
  Commit 55b81528a991 ("doc/filters: itemize crop examples") dropped the
  
  quotation marks from these examples, but this one remained. Quotes are
  
  actually needed to put the example into a command line or a program, but
  
  removing it here makes the example consistent with the document.
  

  • [DH] doc/filters.texi

• Title: Getting "invalid_request_error" when trying to pass converted audio file to OpenAI API

  19 April 2023, by Dummy Cron

  I am working on a project where I receive a URL from a webhook on my server whenever users share a voice note on my WhatsApp. I am using WATI as my WhatsApp API Provder

  


  The file URL received is in the .opus format, which I need to convert to WAV and pass to the OpenAI Whisper API translation task.

  


  I am trying convert it to .wav using ffmpeg, and pass it to the OpenAI API for translation processing.
However, I am getting an "invalid_request_error"

  


  import requests
import io
import subprocess
file_url = #.opus file url
api_key = #WATI API Keu

def transcribe_audio_to_text():
  # Fetch the audio file and convert to wav format

  headers = {'Authorization': f'Bearer {api_key}'}
  response = requests.get(file_url, headers=headers)
  audio_bytes = io.BytesIO(response.content)

  process = subprocess.Popen(['ffmpeg', '-i', '-', '-f', 'wav', '-acodec', 'libmp3lame', '-'], stdin=subprocess.PIPE, stdout=subprocess.PIPE)
  wav_audio, _ = process.communicate(input=audio_bytes.read())

  # Set the Whisper API endpoint and headers
  WHISPER_API_ENDPOINT = 'https://api.openai.com/v1/audio/translations'
  whisper_api_headers = {'Authorization': 'Bearer ' + WHISPER_API_KEY,
                         'Content-Type': 'application/json'}
  print(whisper_api_headers)
  # Send the audio file for transcription

  payload = {'model': 'whisper-1'}
  files = {'file': ('audio.wav', io.BytesIO(wav_audio), 'audio/wav')}

  # files = {'file': ('audio.wav', io.BytesIO(wav_audio), 'application/octet-stream')}

  # files = {'file': ('audio.mp3', io.BytesIO(mp3_audio), 'audio/mp3')}
  response = requests.post(WHISPER_API_ENDPOINT, headers=whisper_api_headers, data=payload)
  print(response)
  # Get the transcription text
  if response.status_code == 200:
      result = response.json()
      text = result['text']
      print(response, text)
  else:
      print('Error:', response)
      err = response.json()
      print(response.status_code)
      print(err)
      print(response.headers)

transcribe_audio_to_text()


  


  Output:

  


  Error: <response>&#xA;400&#xA;{&#x27;error&#x27;: {&#x27;message&#x27;: "We could not parse the JSON body of your request. (HINT: This likely means you aren&#x27;t using your HTTP library correctly. The OpenAI API expects a JSON payload, but what was sent was not valid JSON. If you have trouble figuring out how to fix this, please send an email to support@openai.com and include any relevant code you&#x27;d like help with.)", &#x27;type&#x27;: &#x27;invalid_request_error&#x27;, &#x27;param&#x27;: None, &#x27;code&#x27;: None}}&#xA;</response>

  


• choosing outbound IP (eth0 or eth1) in FFMPEG

  4 September 2018, by Ba Ta

  I have 2 IP addresses on my server.

  $curl --interface eth0 ifconfig.co      
  
  111.111.111.111
  
  
  
   $curl --interface eth0:0 ifconfig.co      
  
  222.222.222.222

  So via curl I can switch via interfaces so my IP address changes when I visit any url based on eth IP

  How can I use same thing via ffmpeg?

  For example, if want to access this video via ffmpeg (it uses 111.111.111.111 to access it)

   ffmpeg -i 123.com/video.mp4

  how can I access same video from my second IP 222.222.222.222 ?

  Is there any command like this, perhaps?

  ffmpeg --interface eth0:0  -i 123.com/video.mp4